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我想像寺庙跑一样创建倾斜效果。我在游戏中有一个角色控制器（玩家）通过控制器向前移动。移动（transform.forward）之后我对其应用倾斜以使其向左倾斜对。以前对于倾斜，我尝试通过使用 transform.translate /tranform.position 直接通过加速度计读数来修改玩家位置，如下所示：

mytransform.translate(acceleration.x*Time.delaTime*5.0f);

但这有一个问题，当我摇动设备时，我的相机开始抖动，播放器也开始抖动，然后我使用以下代码在正 Z 轴上创建倾斜

Vector3 dir = new Vector3(accel.x*8f, 0,0);
    if (dir.sqrMagnitude > 1) 
{
    dir.Normalize();

}
dir.x = Mathf.Round(dir.x * 10f) / 10f;

//mytemp is used for temp storage of player position added with the acceleration 
mytemp = mytransform.position+(mytransform.right*dir.x*Time.deltaTime*5.0f);

Vector3 diffVec=Vector3.zero;
///position of the element on which the player is colliding;
Vector3 col_pos=Collidingelement.transform.position;
Vector3 unitvec=new Vector3(1,0,0);
//removing x and z of the collider
diffVec= Vector3.Scale(col_pos,unitvec);
//nullify the y,z of the updated mytransform position so that the distance is only measured on X
Vector3 ppos = Vector3.Scale(mytemp,unitvec);
//calculate the distance between player & colliding element
 disti=Vector3.Distance( ppos,diffVec);
disti=Mathf.Clamp(disti,-1.5f,1.5f);
disti = Mathf.Round(disti * 10f) / 10f;
//update the player position and apply tilt to it if the distance is less than 1.5f
if(disti<=1.50f)
{
mytransform.position=mytemp;

}

现在有一个问题，如果假设我的加速度值为 0.1，它会继续更新我的温度，如果距离更小，我的玩家将开始向一侧倾斜，尽管我将设备保持在相同的位置并且加速度值为总是 0.1

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1 回答 1

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你为什么不只计算增量加速度。

bool isMoved = false;
Vector2 lastAccel = Vector2.Zero;
Vector2 margin = new Vector2(0.05f, 0.05f);  //not processing if its in margin.
Vector2 deltaAccel = currAccel - lastAccel ;

if(deltaAccel.x < margin.x)
{
   //don't process
   isMove = false;
}
else
{
   isMove = true;
   lastAccel = currAccel;
}

if(isMove)
{
//Process with deltaAccel here
}
于 2013-07-04T07:38:15.860 回答