我有两个班级,这是其中之一的标题:
#ifndef WRAPPER_HPP
#define WRAPPER_HPP
#include <SDL/SDL.h>
using namespace std;
class Wrapper
{
private:
//SDL_Surface *screen;
public:
static SDL_Surface *screen;
static void set_screen(SDL_Surface *_screen);
static void set_pixel(int x, int y, Uint8 color);
static void clear_screen(int r, int g, int b);
static SDL_Surface* load_image(char path[500]);
static void draw_image(SDL_Surface *img, int x, int y, int width, int height);
static void draw_line(int x1, int y1, int x2, int y2, Uint8 color);
};
#endif
我正在从另一个文件中调用 Wrapper::set_screen(screen) 并收到此错误:
In file included from /home/david/src/aships/src/Wrapper.cpp:6:0:
/home/david/src/aships/src/Wrapper.hpp: In static member function ‘static void Wrapper::set_screen(SDL_Surface*)’:
/home/david/src/aships/src/Wrapper.hpp:11:18: error: invalid use of member ‘Wrapper::screen’ in static member function
/home/david/src/aships/src/Wrapper.cpp:10:3: error: from this location
对于 Wrapper.cpp 上的每个函数的定义,我也遇到了类似的错误,例如:
void Wrapper::set_pixel(int x, int y, Uint8 color)
{
/* Draws a pixel on the screen at (x, y) with color 'color' */
Uint8 *p;
p = (Uint8 *) screen->pixels + y * screen->pitch + x * screen->format->BytesPerPixel;
*p = color;
}
编译时:
/home/david/src/aships/src/Wrapper.hpp: In static member function ‘static void Wrapper::set_pixel(int, int, Uint8)’:
/home/david/src/aships/src/Wrapper.hpp:11:18: error: invalid use of member ‘Wrapper::screen’ in static member function
/home/david/src/aships/src/Wrapper.cpp:17:17: error: from this location
我知道它与静态类有关,因此变量 Wrapper.screen 不可访问或其他什么,但我不确定如何修复它。有任何想法吗?