10

ASAIK jquery animate function accepts style properties only. but i want to animate the attributes of an element. consider a SVG element rectangle

<svg>
<rect id="rect1" x=10 y=20 width="100px" height="100px">
</svg>

i want to animate the rectangle element attribute "x" and "y" something like below

$("#rect1").animate({
    x: 30,
    y: 40
  }, 1500 );

but it is not correct way because animate function affects style not attribute of an element.

i knew so many custom plugin is there like raphel.js.

http://raphaeljs.com/

but i don't want to use custom plugin to do this. i want to do this simply in jquery.animate function.

is this possible ?

Thanks,

Siva

4

5 回答 5

6

只需为老式方式制作动画：

你可以像时尚一样调用animatejquery。

http://jsfiddle.net/wVv9P/7/

function animate($el, attrs, speed) {

    // duration in ms
    speed = speed || 400;

    var start = {}, // object to store initial state of attributes
        timeout = 20, // interval between rendering loop in ms
        steps = Math.floor(speed/timeout), // number of cycles required
        cycles = steps; // counter for cycles left

    // populate the object with the initial state
    $.each(attrs, function(k,v) {
        start[k] = $el.attr(k);
    });

    (function loop() {
        $.each(attrs, function(k,v) {  // cycle each attribute
            var pst = (v - start[k])/steps;  // how much to add at each step
            $el.attr(k, function(i, old) {
                return +old + pst;  // add value do the old one
            });
        });

        if (--cycles) // call the loop if counter is not exhausted
            setTimeout(loop, timeout);
        else // otherwise set final state to avoid floating point values
            $el.attr(attrs);

    })(); // start the loop
}

$('button').on('click', function() {       
    animate(
        $('#rect1'), // target jQuery element
        { x:100, y:300, width:50, height:100 }, // target attributes
        2000 // optional duration in ms, defaults to 400
    );
});
于 2013-06-28T09:19:11.670 回答
1

我会尝试这样的事情

<svg>
    <rect class="myElement" id="rect1" x="10" y="20" width="100px" height="100px">
</svg>

在脚本中：

var myElemX = $('.myElement').attr('x');
var myElemY = $('.myElement').attr('y');
$("#rect1").animate({
    left: myElemX+'px',
    top:  myElemY+'px'
}, 1500 );
于 2013-06-28T08:59:05.420 回答
1

好吧，这里的所有答案要么特定于 SVG，要么重新实现 .animate() jQuery 调用，我找到了一种使用 jQuery 调用的方法，而不会遇到动画开始时属性重置为 0 的问题：

假设我们要为带有 id 的 img 标签元素的widthand属性设置动画。要将其从当前值设置为 300 的动画，我们可以这样做：heightimage

var animationDiv= $("<div></div>"); //we don't add this div to the DOM
var image= $("img#image");
//could use any property besides "top" and "left", but the value must be valid, that means concatenating a "px" to numerical attributes if they don't have it already (and removing them in the step callback if they do)
animationDiv.css("left", image.attr("width")); 
animationDiv.css("top", image.attr("height")); 
animationDiv.animate(
    {
        left: 300,
        top: 300
    },
    {
        duration: 2500,
        step: function(value, properties) {
            if (properties.prop == "left")
                 image.attr("width", value + "px")
            else
                 image.attr("height", value + "px")
        }
    }
)

在这种方法中，我们使用一个不在 DOM 内部的 div 并在其中设置动画值，然后我们使用 div CSS 值来为我们的元素设置动画。不是很漂亮，但可以完成工作，如果您需要停止动画，您可以调用.stop()animationDiv。

jsfiddle

于 2014-12-31T10:28:37.870 回答
0

我喜欢 Hoffmann 方法，但我认为不创建虚拟 dom 对象会更优雅。

这是我的咖啡脚本片段

$rects.each ->
  that = @
  $({width: 0}).animate
  width: parseInt($(@).attr('width'))
  ,
  duration: 2000
  easing: 'easeIn'
  step: ->
    $(that).attr 'width', Math.round(@.width)
  done: ->
    console.log 'Done'

编译成

return $rects.each(function() {
  var that;
  that = this;
  return $({
    width: 0
  }).animate({
    width: parseInt($(this).attr('width'))
  }, {
    duration: 1000,
    easing: 'easeIn',
    step: function() {
      return $(that).attr('width', Math.round(this.width));
    },
    done: function() {
      return console.log('Done');
    }
  });
});
于 2015-05-07T10:28:21.253 回答
-1

这可能很适合你

$("your div id").css("position", "absolute").animate({
    left: 159,
    top:  430
});
于 2013-12-22T12:31:47.267 回答