我有一个像下面这样的查询,它给出了以下结果。
询问
select OrderID, AccessName, Address1, Postcode, GeneralInstructions, --CompanyName,
col, --col+'_'+cast(rn as varchar(10)) col,
val
from
(
select o.OrderID, js.JobStatusID, p.Name, o.AccessName, o.Address1, o.Postcode, oj.GeneralInstructions, s.CompanyName
, row_number() over(partition by o.OrderID
order by js.JobStatusID) rn
FROM
NEPCCO.Orders o
inner join NEPCCO.Clients c on o.ClientID = c.ClientID
inner join NEPCCO.OrderJobs oj on o.OrderID = oj.OrderID
inner join NEPCCO.Suppliers s on oj.SupplierID = s.SupplierID
inner join NEPCCO.Products p on oj.ProductID = p.ProductID
inner join NEPCCO.OrderStatus os on o.OrderStatusID = os.OrderStatusID
inner join NEPCCO.JobStatus js on oj.JobStatusID = js.JobStatusID
where
o.OrderID in (50211, 44621) and
(p.ProductID in (35,36,37,38,38,40,41,42,43) or p.ProductID in (33,34))
) d
unpivot
(
val
for col in (Name)
) un
第一个输出
OrderID AccessName Address1 PostCode Col Val
44621 Mr Hayden 7 Broad Rush Green LU7 2XA Name FPA - 28
44621 Mr Hayden 7 Broad Rush Green LU7 2XA Name AW EPR
50211 Mrs Godwin 64 Riverview MK43 7PN Name FPA - 28
另一个查询相同的东西以获得所需的输出
select *
from
(
select OrderID, AccessName, Address1, Postcode, GeneralInstructions, --CompanyName,
col, --col+'_'+cast(rn as varchar(10)) col,
val
from
(
select o.OrderID, js.JobStatusID, p.Name, o.AccessName, o.Address1, o.Postcode, oj.GeneralInstructions, s.CompanyName
, row_number() over(partition by o.OrderID,js.JobStatusID
order by o.OrderID) rn
FROM
NEPCCO.Orders o
inner join NEPCCO.Clients c on o.ClientID = c.ClientID
inner join NEPCCO.OrderJobs oj on o.OrderID = oj.OrderID
inner join NEPCCO.Suppliers s on oj.SupplierID = s.SupplierID
inner join NEPCCO.Products p on oj.ProductID = p.ProductID
inner join NEPCCO.OrderStatus os on o.OrderStatusID = os.OrderStatusID
inner join NEPCCO.JobStatus js on oj.JobStatusID = js.JobStatusID
where
o.OrderID in (50211, 44621) and
(p.ProductID in (35,36,37,38,38,40,41,42,43) or p.ProductID in (33,34))
) d
unpivot
(
val
for col in (Name)
) un
) s
pivot
(
max(val)
for col in (Name,JobStatusID, JobStatusID1, Name1)
) piv
第二个输出接近想要的输出,但不是我想要的
OrderID AccessName Address1 PostCode Col Val
44621 Mr Hayden 7 Broad Rush Green LU7 2XA FPA - 28 NULL
50211 Mrs Godwin 64 Riverview MK43 7PN FPA - 28 NULL
所需输出 - 从第一个查询中检查我要显示的列标题名称
OrderID AccessName Address1 PostCode InstallJobType EPR Type
44621 Mr Hayden 7 Broad Rush Green LU7 2XA FPA - 28 AW EPR
50211 Mrs Godwin 64 Riverview MK43 7PN FPA - 28 NULL
任何帮助将不胜感激,因为我被卡住了
取消透视之前的数据
OrderID JobstatusId Name AccessName Address1 PostCode CompanyName M
44621 3 AW EPR Mr Hayden 7 Broad Rush Green LU7 2XA N/A (Sole trader) 1
44621 14 FPA - 28 Mr Hayden 7 Broad Rush Green LU7 2XA Just Energy Solutions Limited 2
50211 17 FPA - 28 Mrs Godwin 64 Riverview MK43 7PN Just Energy Solutions Limited 1
编辑 - 请检查我是否做得对,因为它提供了我想要的输出
select OrderID, AccessName, Address1, Postcode, GeneralInstructions,
Name_1 as "Install Jobs",
Name_2 as "EPR Jobs",
CompanyName,Name
from
(
select OrderID, AccessName, Address1, Postcode, GeneralInstructions, CompanyName,
col+'_'+cast(rn as varchar(10)) col,
val
from
(
select o.OrderID, js.JobStatusID, p.Name, o.AccessName, o.Address1, o.Postcode, oj.GeneralInstructions, s.CompanyName,
js.Name as "Install Job Status", js.JobStatusID as JS1
, row_number() over(partition by o.OrderID
order by o.OrderID) rn
FROM
NEPCCO.Orders o
inner join NEPCCO.Clients c on o.ClientID = c.ClientID
inner join NEPCCO.OrderJobs oj on o.OrderID = oj.OrderID
inner join NEPCCO.Suppliers s on oj.SupplierID = s.SupplierID
inner join NEPCCO.Products p on oj.ProductID = p.ProductID
inner join NEPCCO.OrderStatus os on o.OrderStatusID = os.OrderStatusID
inner join NEPCCO.JobStatus js on oj.JobStatusID = js.JobStatusID
where
o.OrderID in (50211, 44621) and
(p.ProductID in (35,36,37,38,38,40,41,42,43) or p.ProductID in (33,34))
) d
unpivot
(
val
for col in (Name)
) un
) s
pivot
(
max(val)
for col in (JobStatusID_1, Name_1, JobStatusID_2, Name_2,Name)
) piv