所以实际上我在这里从“Vodemki”获得了一个非常快速和漂亮的代码 - 以 最快的方式获取像素颜色?
但唯一的问题是它扫描整个图像,而我只需要扫描我当前的鼠标位置
这是代码 -
HDC hdc, hdcTemp;
RECT rect;
BYTE* bitPointer;
int x, y;
int red, green, blue, alpha;
while(true)
{
hdc = GetDC(HWND_DESKTOP);
GetWindowRect(hWND_Desktop, &rect);
int MAX_WIDTH = rect.right;
int MAX_HEIGHT = rect.bottom;
hdcTemp = CreateCompatibleDC(hdc);
BITMAPINFO bitmap;
bitmap.bmiHeader.biSize = sizeof(bitmap.bmiHeader);
bitmap.bmiHeader.biWidth = MAX_WIDTH;
bitmap.bmiHeader.biHeight = MAX_HEIGHT;
bitmap.bmiHeader.biPlanes = 1;
bitmap.bmiHeader.biBitCount = 32;
bitmap.bmiHeader.biCompression = BI_RGB;
bitmap.bmiHeader.biSizeImage = MAX_WIDTH * 4 * MAX_HEIGHT;
bitmap.bmiHeader.biClrUsed = 0;
bitmap.bmiHeader.biClrImportant = 0;
HBITMAP hBitmap2 = CreateDIBSection(hdcTemp, &bitmap, DIB_RGB_COLORS, (void**)(&bitPointer), NULL, NULL);
SelectObject(hdcTemp, hBitmap2);
BitBlt(hdcTemp, 0, 0, MAX_WIDTH, MAX_HEIGHT, hdc, 0, 0, SRCCOPY);
for (int i=0; i<(MAX_WIDTH * 4 * MAX_HEIGHT); i+=4)
{
red = (int)bitPointer[i];
green = (int)bitPointer[i+1];
blue = (int)bitPointer[i+2];
alpha = (int)bitPointer[i+3];
x = i / (4 * MAX_HEIGHT);
y = i / (4 * MAX_WIDTH);
if (red == 255 && green == 0 && blue == 0)
{
SetCursorPos(x,y);
mouse_event(MOUSEEVENTF_LEFTDOWN, 0, 0, 0, 0);
Sleep(50);
mouse_event(MOUSEEVENTF_LEFTUP, 0, 0, 0, 0);
Sleep(25);
}
}
}
我不熟悉BitBlt,所以如果有人可以帮助我修改该代码,我将不胜感激
谢谢!