我不能使用 xPath 来查询我的 xml 文件。我不知道错误在哪里,这是我的架构
<?xml version="1.0" encoding="UTF-8"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://xml.netbeans.org/schema/Manufacturers"
xmlns="http://xml.netbeans.org/schema/Manufacturers"
elementFormDefault="qualified">
<xsd:element name="ManufacturerList">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="Manufacturer" type="manufacturerType" maxOccurs="unbounded" />
</xsd:sequence>
</xsd:complexType>
</xsd:element>
<xsd:complexType name="manufacturerType">
<xsd:sequence>
<xsd:element name="ManufacturersID" type="xsd:positiveInteger"/>
<xsd:element name="ManufacturersName" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
这是我使用 marshall 生成 xml 文件后的 xml 文件
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ManufacturerList xmlns="http://xml.netbeans.org/schema/Manufacturers">
<Manufacturer>
<ManufacturersID>1</ManufacturersID>
<ManufacturersName>SamSung</ManufacturersName>
</Manufacturer>
<Manufacturer>
<ManufacturersID>2</ManufacturersID>
<ManufacturersName>Apple</ManufacturersName>
</Manufacturer>
<Manufacturer>
<ManufacturersID>3</ManufacturersID>
<ManufacturersName>Nokia</ManufacturersName>
</Manufacturer>
这是我的 xsl 文件
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:manu="http://xml.netbeans.org/schema/Manufacturers"
exclude-result-prefixes="manu" version="1.0">
<xsl:output method="html"/>
<xsl:template match="/">
<html>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
<xsl:template match="/">
<xsl:for-each select="/manu:Manufacturer">
<li>
<a href="#">
<xsl:value-of select="manu:ManufacturersName"/>
</a>
</li>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
在运行网页时的jsp文件中,我无法得到我想要的结果。xsl 文件无法使用 xpath 查询读取 xml 文件