0

我有一个 $_POST 数组，目前采用以下形式：

 ["Area"]=> array(2) { 
    [0]=> string(5) "Title" 
    [1]=> string(5) "Title" 
    } 
 ["Issue"]=> array(2) { 
    [0]=> string(3) "111" 
    [1]=> string(7) "2222222" 
    } 
 ["Elevation"]=> array(2) { 
    [0]=> string(8) "11111111" 
    [1]=> string(7) "2222222" 
    } 
 ["Fix"]=> array(2) { 
    [0]=> string(8) "11111111" 
    [1]=> string(6) "222222" 
    } 
 ["ExpectFee"]=> array(2) { 
    [0]=> string(8) "11111111" 
    [1]=> string(5) "22222" 
    } 
 ["Outlay"]=> array(2) { 
    [0]=> string(9) "111111111" 
    [1]=> string(9) "222222222" 
    } 
 ["ExpctTime"]=> array(2) { 
    [0]=> string(9) "111111111" 
    [1]=> string(11) "22222222222" 
 } 
 ["Checkbox"]=> array(2) { 
    [0]=> string(12) "111111111111" 
    [1]=> string(11) "22222222222" 
    }

我目前正在像这样循环...

 if ($_POST['OthProb']['Issue'] != '') {
       $table = 'tbl_customproblems';
       $kv = array();

            foreach ($_POST['OthProb'] as $array) {
                foreach ($array as $value) {
                    $kv[] = "'".$value."'";

            }
            $string = "INSERT INTO $table (AccountID, myID, Area, Issue, Elevation, Fix, ExpectFee, Outlay, ExpctTime, Checkbox) VALUES ('$_POST[AccountID]', '$_POST[myID]', ".join(", ", $kv).")";     
        }

} else {
  $string = $_SERVER['QUERY_STRING'];
}

$sql = $DBH->prepare($string);
$sql->execute();

这几乎可以工作！它产生这个...

"INSERT INTO tbl_customproblems (AccountID, PropertyID, Area, Issue, Elevation, Fix, ExpectFee, Outlay, ExpctTime, WHCheckbox) VALUES ('81', '81', 'Title', 'Title', '111', '2222222', '11111111', '2222222', '11111111', '222222', '11111111', '22222', '111111111', '222222222', '111111111', '22222222222', '111111111111', '22222222222')"

如何修改循环以生成单独的插入，每行一个插入。

4

2 回答 2

1

它必须是这样的：

if ($_POST['OthProb']['Issue'] != '') {
$table = 'tbl_customproblems';
$string = 'INSERT INTO $table (AccountID, myID, Area, Issue, Elevation, Fix, ExpectFee, Outlay, ExpctTime, Checkbox) VALUES (:AccountID, :myID, :Area, :Issue, :Elevation, :Fix, :ExpectFee, :Outlay, :ExpctTime, :Checkbox)';

$sql = $DBH->prepare($string);

$i = 0;
foreach ($_POST['OthProb'] as $array) {

    $sql->bindParam(':AccountID', $_POST['AccountID'], PDO::PARAM_INT);
    $sql->bindParam(':myID', $_POST['myID'], PDO::PARAM_INT);
    $sql->bindParam(':Area', $array['area'][$i], PDO::PARAM_STR); //it can also be PDO::PARAM_STR

        $sql->execute();
        $i++;
    }
}

我没有绑定所有参数，所以你必须自己做，我希望你能通过这个例子了解准备语句。

在您需要整数时使用的准备语句中PDO::PARAM_INT，您将使用PDO::PARAM_STR字符串。当您不确定它是整数还是字符串时，您最好使用PDO::PARAM_STR

于 2013-06-20T15:38:54.657 回答
0

我最终使用下面的代码得到了它，它可能是最大的hacky，我打算在未来对其进行改进，但它可以工作。

if ($_POST['OthProb']['Issue'] != '') {
       $kv = array();
       // This will help control the array index
       $i = 0;
       // count the number of records in the array
       $count = count($_POST['OthProb']['Area']);
       $table = 'tbl_customproblems';

       // Loop through each index - stop before we reach the value of count.
       for ($i=0; $i < $count; $i++) {
           // Catch the data
           foreach ($_POST['OthProb'] as $value) {
                    $kv[] = "'".$value[$i]."'";       
            }
        // Do the insert!
        $string = "INSERT INTO $table (AccountID, PropertyID, Area, Issue, Elevation, Fix, ExpectFee, Outlay, ExpctTime, Checkbox) VALUES ('$_POST[AccountID]', '$_POST[PropertyID]', ".join(", ", $kv).") ";
        $sql = $DBH->prepare($string);
        $sql->execute();
        // Unset data value to prevent retention
        unset ($kv);  
        }
于 2013-06-21T09:48:34.857 回答