1 
<?php
$con=mysqli_connect("localhost","*********","***********","loadtracker");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}  
$result = mysqli_query($con,"SELECT Date FROM pallettracker GROUP BY Date");
$DateList = mysqli_fetch_array($result);
$ListOfMonths=array('Dec','Nov','Oct','Sep','Aug','Jul','Jun','May','Apr','Mar','Feb','Jan');$ListOfDays = array('31','30','29','28','27','26','25','24','23','22','21','20','19','18','17','16','15','14','13','12','11','10','9','8','7','6','5','4','3','2','1');
foreach ($ListOfDays as $value) {
foreach ($ListOfMonths as $value2) {
$Yaer = array("'$value2' + '$value' + ',2013'");
foreach ($Yaer as $yaerdate) {
 foreach ($DateList as $Dates) {
     if ($yaerdate == $Dates)
     {
         echo $yaerdate;
         echo '/';
     }
 } 
 }
 } 
 }
 ?>

尝试订购格式为 Jan28,2013 和 Decending 的日期数组。然后在它们之间显示 / 。对于 Android 应用程序

4

2 回答 2

0

我不明白，为什么在不使用分组功能时使用 GROUP BY。这里更好的方法是 DISTINCT

我会以这种方式更新您的代码：

$result = mysqli_query($con,"SELECT DISTINCT `Date` FROM `pallettracker` ORDER BY `Date` DESC");
while($date = mysqli_fetch_assoc($result)
{
    echo date('',strtotime($date['Date'])).'<br />';
}

重要的是，您在 mysql 中的“日期”列的格式为日期或日期时间

于 2013-06-20T08:26:14.827 回答
0

您可以让您的 SQL 查询为您订购它们。这假设该列是日期格式。如果不是这样，请查看：SQL ORDER BY date question。

在查询中订购后，您只需将其转换为时间，然后根据需要格式化日期。这可能会给你你正在寻找的东西：

<?

$datetime = strtotime($row->createdate);
$mysqldate = date("m/d/y g:i A", $datetime);

$result = mysqli_query($con,"SELECT Date FROM pallettracker GROUP BY Date");

foreach($result as $date){
    $datetime = strtotime($result);
    $date = date("M d, y", $datetime);
    echo $date . '/';
}

?>
于 2013-06-20T01:39:16.087 回答