python - 删除Python列表中没有数字的单词的方法是什么？

Question

 a = ['in 1978 by', 'History', 'members', 'albums', 'June 4th, 1979', 'October 7,1986): "The Lounge', 'In 1984 the', 'early 1990s; prominent']

上面的列表有历史之类的词，成员中没有数字，所以我想删除它们

 # output would be
 a = ['in 1978 by', 'June 4th, 1979', 'October 7, 1986', 'In 1984 the', 'early 1990s; prominent']

Answer 1

保留你想要的：

a = ['in 1978 by', 'History', 'members', 'albums', 'June 4th, 1979', 'October 7,1986): "The Lounge', 'In 1984 the', 'early 1990s; prominent']

new = [el for el in a if any(ch.isdigit() for ch in el)]
# ['in 1978 by', 'June 4th, 1979', 'October 7,1986): "The Lounge', 'In 1984 the', 'early 1990s; prominent']

Answer 2

这是一个较短的替代方案，使用any()and string.digits：

from string import digits

a = ['in 1978 by', 'History', 'members', 'albums', 'June 4th, 1979', 
     'October 7,1986): "The Lounge', 'In 1984 the', 'early 1990s; prominent']

[x for x in a if any(y in x for y in digits)]

=> ['in 1978 by', 'June 4th, 1979', 'October 7,1986): "The Lounge',
    'In 1984 the', 'early 1990s; prominent']

Answer 3

使用正则表达式和列表推导，这是一个单行：

import re
[i for i in a if re.search('\d', i) is not None]