0

[免责声明：我是PHP的新手，我只是在学习，所以请不要喷，当人们试图寻找解决方案或信息时，它确实阻碍了学习过程，谢谢，代码在填字游戏方面工作正常，这真的让我很困惑，一个人如何通过给定的信息获得对角线方向，或者我做错了什么而没有看到？]

给定一个开关：

  switch ($dir){
case "E":
  //col from 0 to board width - word width
  //row from 0 to board height
  $newCol = rand(0, $boardData["width"] - 1 - strlen($theWord)); 
  $newRow = rand(0, $boardData["height"]-1);

  for ($i = 0; $i < strlen($theWord); $i++){
    //new character same row, initial column + $i
    $boardLetter = $board[$newRow][$newCol + $i];
    $wordLetter = substr($theWord, $i, 1);

    //check for legal values in current space on board
    if (($boardLetter == $wordLetter) ||
        ($boardLetter == ".")){
      $board[$newRow][$newCol + $i] = $wordLetter;
    } else {
      $itWorked = FALSE;
    } // end if
  } // end for loop
  break;

和：

case "N":
  //col from 0 to board width
  //row from word length to board height
  $newCol = rand(0, $boardData["width"] -1);
  $newRow = rand(strlen($theWord), $boardData["height"]-1);

  for ($i = 0; $i < strlen($theWord); $i++){
    //check for a legal move
    $boardLetter = $board[$newRow - $i][$newCol];
    $wordLetter = substr($theWord, $i, 1);
    if (($boardLetter == $wordLetter) ||
        ($boardLetter == ".")){
      $board[$newRow - $i][$newCol] = $wordLetter;
    } else {
     $itWorked = FALSE;
    } // end if
  } // end for loop
  break;

我应该能够将两者结合起来得到 NE（或对角线文本输出到屏幕上）

但是，当我尝试这个时，它不起作用，我一直在尝试 N 和 E 的不同组合以获得 NE 或对角 NE 方向，但没有运气，是什么给出的？

#Tried multiple different combination's of N & E, I am out of ideas 

switch ($dir){
case "E":

  $newCol = rand(0, $boardData["width"] - 1 - strlen($theWord)); 
  $newRow = rand(strlen($theWord), $boardData["height"]-1);


  for ($i = 0; $i < strlen($theWord); $i++){
  #Combined but no luck, WTF:

    $boardLetter = $board[$newRow][$newRow - $i];
     $boardLetter  = $board[$newCol][$newCol + $i];
    $wordLetter = substr($theWord, $i, 1);

    //check for legal values in current space on board
    if (($boardLetter == $wordLetter) ||
        ($boardLetter == ".")){

      $board[$newRow][$newRow - $i] = $wordLetter;
      $board[$newCol][$newCol + $i] = $wordLetter;
    } else {
      $itWorked = FALSE;
    } // end if
  } // end for loop
  break;
4

1 回答 1

2

运行代码后，该break;语句将跳出子句。您需要为组合设置新的、明确的案例，以使其以这种方式工作。switchcase "E"

于 2009-11-11T06:47:02.520 回答