1 
out_file = open('result.txt', 'w')
A = [1,2,3,4,5,6,7,8,9,10]
B = [11,12,13,14,15]
for a in A:
    for b in B:
        result = a + b
        print (result, file = out_file)
out_file.close()

上述程序将所有结果（50 个元素）一起写入一个输出文件（result.txt）。

我想写出十个文件，每个文件由 5 个元素组成，命名如下：

1.txt

2.txt

...

10.txt

1.txt 文件将放置 1+11、1+12、1+13、1+14 和 1+15 的总和。

2.txt 文件将放入 2+11、2+12、2+13、2+14 和 2+15 的总和。

......

10.txt 文件将放置 10+11、10+12、10+13、10+14 和 10+15 的总和。

任何帮助，请。预计非常简单的程序。

同样，当我想使用 N 的元素命名输出文件时，为什么我不能呢？

A = [1,2,3,4,5,6,7,8,9,10]
B = [11,12,13,14,15]
N = ['a','b','c','d','e','f','g','h','i','j']
for a in A:
    results = []
    for b in B:
        result = a + b
        results.append(result)
        for n in N:
            with open('{}.txt'.format(n),'w') as f:
                for res in results:
                    f.write(str(res)+'\n')
4

3 回答 3

2 
A = [1,2,3,4,5,6,7,8,9,10]
B = [11,12,13,14,15]
for a in A:
    results = []           # define new list for each item in A
    #loop over B and collect the result in a list(results)
    for b in B:
        result = a + b
        results.append(result)   #append the result to results
    #print results               # uncomment this line to see the content of results
    filename = '{}.txt'.format(a)      #generate file name, based on value of `a`
    #always open file using `with` statement as it automatically closes the file for you
    with open( filename , 'w') as f:
       #now loop over results and write them to the file
       for res in results:
          #we can only write a string to a file, so convert numbers to string using `str()`
          f.write(str(res)+'\n') #'\n' adds a new line

更新：

你可以zip()在这里使用。zip从传递给它的序列中返回相同索引上的项目。

A = [1,2,3,4,5,6,7,8,9,10]
B = [11,12,13,14,15]
N = ['a','b','c','d','e','f','g','h','i','j']
for a,name in zip(A,N):
    results = []
    for b in B:
        result = a + b
        results.append(result)
    filename = '{}.txt'.format(name)
    with open( filename , 'w') as f:
       for res in results:
           f.write(str(res)+'\n')

帮助zip：

>>> print zip.__doc__
zip(seq1 [, seq2 [...]]) -> [(seq1[0], seq2[0] ...), (...)]

Return a list of tuples, where each tuple contains the i-th element
from each of the argument sequences.  The returned list is truncated
in length to the length of the shortest argument sequence.
于 2013-06-11T10:41:03.017 回答
1 
A = [1,2,3,4,5,6,7,8,9,10]
B = [11,12,13,14,15]
for a in A:
    with open(str(a) + '.txt', 'w') as fout:
        fout.write('\n'.join(str(a + b) for b in B)
于 2013-06-11T10:45:34.650 回答
0 
A = range(1, 10 + 1)
B = range(11, 15 + 1)

for a in A:
    with open('{}.txt'.format(a), 'wb') as fd:
        for b in B:
            result = a + b
            fd.write('{}\n'.format(result))
于 2013-06-11T10:46:46.047 回答