0

首先，这是我的 json 输出。

{"alert_id":"1","type":"Urgent","department":"Engineering Department","clas":"4","faculty":"Software Engineering","body":"Mike" “日期”：“10.04.1990”}

这是解析代码。

package com.androidalert;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;

import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.Activity;
import android.os.Bundle;
import android.widget.EditText;

public class AlertsJSON extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.alert);

        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://www.tuncayyildirim.com.tr/cagri_android_frontend/event_restful/event_handler/get_event.json");

        EditText textID = (EditText) findViewById(R.id.textID);
        EditText textType = (EditText) findViewById(R.id.textType);
        EditText textDepartment = (EditText) findViewById(R.id.textDepartment);
        EditText textClass = (EditText) findViewById(R.id.textClass);
        EditText textFaculty = (EditText) findViewById(R.id.textFaculty);
        EditText textBody = (EditText) findViewById(R.id.textBody);
        EditText textDate = (EditText) findViewById(R.id.textDate);

        textID.setKeyListener(null);
        textType.setKeyListener(null);
        textDepartment.setKeyListener(null);
        textClass.setKeyListener(null);
        textFaculty.setKeyListener(null);
        textBody.setKeyListener(null);
        textDate.setKeyListener(null);

        try {

            HttpResponse response = httpclient.execute(httppost);
            String jsonResult = inputStreamToString(
                    response.getEntity().getContent()).toString();
            JSONObject object = new JSONObject(jsonResult);

            String id = object.getString("alert_id");
            String type = object.getString("type");
            String department = object.getString("department");
            String clas = object.getString("clas");
            String faculty = object.getString("faculty");
            String body = object.getString("body");
            String date = object.getString("date");

            textID.setText(id);
            textType.setText(type);
            textDepartment.setText(department);
            textClass.setText(clas);
            textFaculty.setText(faculty);
            textBody.setText(body);
            textDate.setText(date);

        } catch (JSONException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    private StringBuilder inputStreamToString(InputStream is) {
        String rLine = "";
        StringBuilder answer = new StringBuilder();
        BufferedReader rd = new BufferedReader(new InputStreamReader(is));

        try {
            while ((rLine = rd.readLine()) != null) {
                answer.append(rLine);
            }
        }
        catch (IOException e) {
            e.printStackTrace();
        }
        return answer;
    }
}

我认为，代码是正确的，但我无法在我的应用程序中显示 JSON 输出。

4

1 回答 1

0

JSON 对象解析看起来是正确的，所以问题出在其他地方。首先，您不应该（并且实际上不能在最新的 sdks 中）在 UI 线程上进行网络连接。另外，如果它接收到实际的 json，我会在解析之前检查您的“jsonResult”值。

于 2013-06-10T22:29:38.227 回答