我正在使用带有以下代码的头文件:
<?php
    $ADMIN = False;
   if(session_id() == '') {
   // session has NOT been started
     session_start();
   }
   else
    {
         // session has been started
      }
  ?>
我必须检查管理变量状态的代码是这样的:
    while ($row2 = mysql_fetch_array($account_type)){
    if($row2['account_type'] == 'A'){
        $ADMIN = 'true';}
        else{$ADMIN = 'false';}
每次我尝试访问带有该站点的页面时,都会出现错误:
Parse error: syntax error, unexpected '$ADMIN' (T_VARIABLE)