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我的代码:

SecKeyRef oPublicKey = [self getPublicKeyRef];
SecKeyRef oPrivateKey = [self getPrivateKeyRef];

CFDictionaryRef myDictionary;

CFTypeRef keys[2];
CFTypeRef values[2];

// Initialize dictionary of key params
keys[0] = kSecAttrKeyType;
values[0] = kSecAttrKeyTypeRSA;
keys[1] = kSecAttrKeySizeInBits;
int iByteSize = 1024;
values[1] = CFNumberCreate( NULL, kCFNumberIntType, &iByteSize );
myDictionary = CFDictionaryCreate( NULL, keys, values, sizeof(keys) / sizeof(keys[0]), NULL, NULL );

// Generate keys
OSStatus status = SecKeyGeneratePair( myDictionary, &oPublicKey, &oPrivateKey );
if ( status != 0 )
    NSLog( @"SecKeyGeneratePair failed" );

// Encrypt some data
uint8_t* pPlainText = (uint8_t*)"6921";

uint8_t aCipherText[1024];
size_t iCipherLength = 1024;
status = SecKeyEncrypt( oPublicKey, kSecPaddingPKCS1, pPlainText, strlen( (char*)pPlainText ) + 1, &aCipherText[0], &iCipherLength );

if ( status != 0 )
    NSLog( @"SecKeyEncrypt failed" );

NSMutableData *data12=[[NSMutableData alloc] init];
[data12 appendBytes:aCipherText length:strlen( (char*)aCipherText ) + 1];
NSString *string1 = [[NSString alloc]initWithData:data12 encoding:NSASCIIStringEncoding];
NSLog(@"Encrypted Text:::%@",string1);

// Decrypt the data
uint8_t aPlainText[1024];
size_t iPlainLength = 1024;
status = SecKeyDecrypt( oPrivateKey, kSecPaddingPKCS1, &aCipherText[0], iCipherLength, &aPlainText[0], &iPlainLength );
if ( status != 0 )
    NSLog( @"SecKeyDecrypt failed" );

NSLog(@"FINAL decrypted text: %s", aPlainText);

我正在使用此代码进行加密,但我们得到的输出如下:

N$) : )¥= wÞ¢#4+ 'MO, œÝÕ' #2< xÕ ™'Hþ a  f¦ šU;f£Æì ø¤VØ´ÿ ÷ påcx ¨¢¯Ô)Õ#k Ë« : çÑ5 õ°7\Û ‰z~“9GX>M¼êe뿆w¥ro¬ ›gP4s2µ)9; p

但是如何获取 NSString 格式?我的代码中是否有任何错误步骤?

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1 回答 1

0

总是填充你的纯文本PKCS #1是 RSA 加密的标准填充。

另外,请注意,使用 RSA 公钥加密,您只能加密/解密数据,直到密钥大小(减去一些开销字节)。

公钥加密通常仅用于加密密钥(和散列),然后将其用于实际有效负载的对称加密(和验证)。

于 2013-05-31T12:44:21.123 回答