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是否可以使用 SLComposerViewController 回复推文？以前有人做过吗？

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2 回答 2

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好的，我们goooo。首先，我们需要在每次点击回复按钮时生成一个 SLComposeViewController。启动 SLComposeViewController 后，我们深入研究它并搜索“发送”按钮并禁用名为sendButtonTapped:. 在剥离原生操作后，我们将我们自己的自定义操作关联到 sendButton。

这是执行此操作的代码：

if([SLComposeViewController isAvailableForServiceType:SLServiceTypeTwitter])
                {
                    userTypedTweet = [SLComposeViewController composeViewControllerForServiceType:SLServiceTypeTwitter];
                    [userTypedTweet setInitialText:[NSString stringWithFormat:@"%@",authorName]];
                     sendButton = [self tweetSendButton:userTypedTweet.view];
                    NSLog(@"%@",sendButton);
                    NSArray * actions = [sendButton actionsForTarget:userTypedTweet forControlEvent:UIControlEventTouchUpInside];
                    for (NSString * action in actions)
                     if([action isEqualToString:@"sendButtonTapped:"])
                        [sendButton removeTarget:userTypedTweet action:NSSelectorFromString(action) forControlEvents:UIControlEventTouchUpInside];
                    [sendButton addTarget:self action:@selector(replyToTheTweet) forControlEvents:UIControlEventTouchUpInside];
                    [self presentViewController:userTypedTweet animated:YES completion:^{}];
                }

现在在我们的自定义操作中（在我的例子中为replyToTweet）：我们提取用户输入的评论。然后将所有这些传递给 Twitter API。Twitter 会处理剩下的事情！！

-(void)replyToTheTweet
{
    SingletonClass *myAccount= [SingletonClass sharedobject];
    UITextView * textView = [self tweetTextView:self.userTypedTweet.view];
    NSLog(@"we have the value :%@",textView.text);
    NSMutableDictionary *parameters = [[NSMutableDictionary alloc] init];
        [parameters setObject:[myAccount.currentTweet objectForKey:@"id_str"] forKey:@"in_reply_to_status_id"];
        [parameters setObject:textView.text forKey:@"status"];
    SLRequest *request = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/update.json"] parameters:parameters];
NSLog(@"%@",request.parameters);
   [request performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
   if (responseData)
        {
            NSError *parseError = nil;
            id json = [NSJSONSerialization JSONObjectWithData:responseData options:0 error:&parseError];
            if (!json)
                NSLog(@"Parse Error: %@", parseError);
            else
            {
                UIAlertView *alertOK = [[UIAlertView alloc] initWithTitle:@"Successful" message:@"Tweet was succesfully replied to" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
                dispatch_async(dispatch_get_main_queue(), ^{[alertOK show];});
            }
     }
     else
     {
     NSLog(@"Request Error: %@", [error localizedDescription]);
     }
     }];
    [self.userTypedTweet dismissViewControllerAnimated:YES completion:nil];
}

剥离 UiTextView 的代码是：

  - (UITextView *)tweetTextView:(UIView *)view
    {
        for (UIView * subview in view.subviews)
        {
            if ([subview isMemberOfClass:[UITextView class]])
                return (UITextView *)subview;
            UITextView * textView = [self tweetTextView:subview];
            if (textView) return textView;
        }
        return nil;
    }

IMP：记得把 SLComposeViewController 的 UIButton 也去掉！！

于 2013-05-30T10:38:43.783 回答
0

由于 SLComposeViewController 继承自 View Contoller，我们需要将 SLComposeViewcontroller 剥离到它的 UITextView 属性并获取其内容。然后我们将收集到的信息与"in_reply_to_status_id". 轻松活泼的！！如果您需要代码方面的帮助，请让我知道！剧透 我还没有实现它.. 但由于我能够从 SLComposerViewController 检索用户输入，我认为剩下的将是小菜一碟

于 2013-05-29T16:34:42.313 回答