1 
int main()
{
printf("Welcome to the temperature control program:\n");
    printf("enter the ascii temperature characters");
    printf("enter the ascii characters of an euipment name with + or - and followed by a integer value");
    printf("type character terminated by carriage return");

    char tbuffer [tbuffer_length];
    printf("enter the temperature value");
    scanf("%7c", tbuffer);
    char *t;
    t = fgets (tbuffer, tbuffer_length, stdin );
    if(tbuffer[0] = 'A')
    {

    }
    if (tbuffer[0] = 'B')
    {

    }
    if (tbuffer[0] = 'C')
    {

    }

return 0;
}

在这种情况下，用户输入字符串值（例如：char buffer[7]= {'A', '+', '2', '5', '.','5','\r'} ) 如何将此字符串解释为 A 有设备 A 或 B 有设备 B，+25.5 有温度值（我想将此温度值转换为整数）和回车。在解释并将其转换为整数后，我需要通过接口发送（我知道如何通过接口发送）。给我一些解释的想法。

4

2 回答 2

0

在您的代码scanf("%7c", tbuffer);中应该是scanf("%7s", tbuffer);.

也if(tbuffer[0] = 'A')应该是if(tbuffer[0] == 'A')。其他if语句也一样。

要将字符串转换为整数，请尝试以下代码，

char temp[10];
int dec,frac; 



if(tbuffer[0] = 'A')
{
   i=2;
   j=0;
   while(tbuffer[i] != '.')
   {
      temp[j]=tbuffer[i];
      j++;
      i++;
   }
   temp[j]='\0';
   dec=atoi(temp);
   j=0;
   i++;
   while(tbuffer[i] != '\0')
   {
      temp[j]=tbuffer[i];
      j++;
      i++;
   }   
   temp[j]='\0';
   frac=atoi(temp);
}

现在变量dec包含小数部分并frac包含分数。

例如，如果buffer[7]= {'A', '+', '2', '5', '.','5','\0'};那么dec = 25和frac = 5。

于 2013-05-28T14:44:35.643 回答
0

使用 == 运算符比较值

int main()
{
printf("Welcome to the temperature control program:\n");
    printf("enter the ascii temperature characters");
    printf("enter the ascii characters of an euipment name with + or - and followed by a integer value");
    printf("type character terminated by carriage return");

    char tbuffer [tbuffer_length];
    printf("enter the temperature value");
    scanf("%7c", tbuffer);
    char *t;
    t = fgets (tbuffer, tbuffer_length, stdin );
    if(tbuffer[0] == 'A')
    {

    }
    if (tbuffer[0] == 'B')
    {

    }
    if (tbuffer[0] == 'C')
    {

    }

return 0;
}
于 2013-05-28T14:31:17.830 回答