2

如何将一个很长的mysql线串转换为数组（逐点）的最佳方法，我认为使用explode是一种方法，但在传递字符串参数之前它需要一点点文本操作才能爆炸。

这是查询结果的 var_dump：

array (size=1)
    'route' => string 'LINESTRING(-25.3233034167988 -57.640113830566406,-25.3229348965009 -57.64023184776306,-25.322653656571582 -57.63954520225525,-25.323410093517822 -57.63928771018982,-25.3229058027454 -57.6378607749939,-25.322973688164012 -57.63678789138794,-25.323371301994506 -57.63360142707825,-25.322003892857673 -57.633676528930664,-25.31995759927745 -57.633376121520996,-25.319336915717006 -57.63331174850464,-25.317988857651912 -57.63302206993103,-25.317377862364236 -57.63294696807861,-25.317688209562228 -57.62954592704773'... (length=4354)

目标是有一个这样的数组：路线：

array (size=4354)
    0 => { x=> '-25.3233034167988', y=> '-57.640113830566406'}
    1 => { x=> '-25.3229348965009 ', y=> '-57.64023184776306'}

等等

使用 nickb 代码，结果是：

array (size=112)
  0 => 
    array (size=2)
      'x' => string '-25.3233034167988' (length=17)
      'y' => string '-57.640113830566406' (length=19)
  1 => 
    array (size=2)
      'x' => string '-25.3229348965009' (length=17)
      'y' => string '-57.64023184776306' (length=18)
  2 => 
    array (size=2)
      'x' => string '-25.322653656571582' (length=19)
      'y' => string '-57.63954520225525' (length=18)

完美的

4

3 回答 3

1

我认为解析字符串的更有效方法。

$route = 'LINESTRING(-25.3233034167988 -57.640113830566406,-25.3229348965009 -57.64023184776306,-25.322653656571582 -57.63954520225525)';
preg_match_all('/([0-9.\-]+) ([0-9.\-]+)/', $route, $matches);

$result = array_map(function($x, $y)
    {
    return ['x' => $x, 'y' => $y];
    }, $matches[1], $matches[2]);

var_dump($result);
于 2014-09-18T08:16:37.857 回答
1

我会做一些简单的字符串操作，然后形成数组str_getcsv()：

$str = $array['route']; // Get the string from the array
// Get rid "LINESTRING(" and trailing ")"
$str = substr( $str, 11, (strlen( $str) - 1) - 11);

现在，您只需要输入您的x和y键，如下所示：

// Form the objective array:
$objective = array();
foreach( str_getcsv( $str) as $k => $v) {
    list( $x, $y) = explode( ' ', $v);
    $objective[$k]['x'] = $x;
    $objective[$k]['y'] = $y;
}

您可以从这个演示中看到这将打印：

Array ( [0] => Array ( [x] => -25.3233034167988 [y] => -57.640113830566406 ) ... etc ...)
于 2013-05-28T14:22:53.150 回答
0

我认为您可以使用两次explode 函数来创建新数组，然后循环遍历它并按预期分配键

$string = array('route' => 'LINESTRING(-25.3233034167988 -57.640113830566406,-25.3229348965009 -57.64023184776306,-25.322653656571582 -57.63954520225525,-25.323410093517822 -57.63928771018982,-25.3229058027454 -57.6378607749939,-25.322973688164012 -57.63678789138794,-25.323371301994506 -57.63360142707825,-25.322003892857673 -57.633676528930664,-25.31995759927745 -57.633376121520996,-25.319336915717006 -57.63331174850464,-25.317988857651912 -57.63302206993103,-25.317377862364236 -57.63294696807861,-25.317688209562228 -57.62954592704773');
$new_array = array();
$final_array = array();
foreach($string as $data)
{
    $array = explode(',', $data);
    foreach($array as $value)
    {
        $new_array []= explode(' ', str_replace('LINESTRING(', '', $value));
    }

    $array_key = array('x', 'y');
    foreach($new_array as $val)
    {
        $final_array []= (array_combine($array_key, $val));
    }
}

var_dump($final_array);

这将输出

array (size=13)
  0 => 
    array (size=2)
      'x' => string '-25.3233034167988' (length=17)
      'y' => string '-57.640113830566406' (length=19)
  1 => 
    array (size=2)
      'x' => string '-25.3229348965009' (length=17)
      'y' => string '-57.64023184776306' (length=18)
  2 => 
    array (size=2)
      'x' => string '-25.322653656571582' (length=19)
      'y' => string '-57.63954520225525' (length=18)
  3 => 
    array (size=2)
      'x' => string '-25.323410093517822' (length=19)
      'y' => string '-57.63928771018982' (length=18)
  4 => 
    array (size=2)
      'x' => string '-25.3229058027454' (length=17)
      'y' => string '-57.6378607749939' (length=17)
  5 => 
    array (size=2)
      'x' => string '-25.322973688164012' (length=19)
      'y' => string '-57.63678789138794' (length=18)
     //and so on
于 2013-05-28T14:34:17.170 回答