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恐怕我想做的事情根本不可能，但我希望你能帮助我找到解决这个问题的好方法。

我有以下 PHP 数组：

Array ( 
    [0] => Array ( [article] => 10.499-1 [operation] => KN_KABEL [date] => 31-05-2013 [hours] => 0 [quantity] => 1 ) 
    [1] => Array ( [article] => 10.499-1 [operation] => LAS_LABEL [date] => 31-05-2013 [hours] => 0 [quantity] => 1 ) 
    [2] => Array ( [article] => 10.499-1 [operation] => ASS_HARNES [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [3] => Array ( [article] => 10.499-1 [operation] => CONTROLE [date] => 07-06-2013 [hours] => 0 [quantity] => 1 ) 
    [4] => Array ( [article] => 24.030 [operation] => LAS_LABEL [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [5] => Array ( [article] => 24.030 [operation] => ZAGEN-RAIL [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [6] => Array ( [article] => 24.030 [operation] => KN_KABEL [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [7] => Array ( [article] => 24.030 [operation] => ASS_RAIL [date] => 05-06-2013 [hours] => 0 [quantity] => 1 ) 
    [8] => Array ( [article] => 791 070-6/GS/P [operation] => GS_UNIT [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [9] => Array ( [article] => 791 070-6/GS/P [operation] => PR_UNIT [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [10] => Array ( [article] => 791 070-6/GS/P [operation] => LAS_LABEL [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [11] => Array ( [article] => ESS-0834E/LE-CD200 [operation] => MAGAZIJN [date] => 10-06-2013 [hours] => 0 [quantity] => 1 ) 
    [12] => Array ( [article] => ESS-0834E/LE-CD200 [operation] => PR_UNIT [date] => 11-06-2013 [hours] => 0 [quantity] => 1 ) 
    [13] => Array ( [article] => ESS-0834E/LE-CD200 [operation] => LAB_PLAKKE [date] => 11-06-2013 [hours] => 0 [quantity] => 1 )
)

我想要做的是计算每个日期（键“基准”）的小时总和（在这个例子中它们都是 0，但我仍然想这样做，因为这将在未来发生变化）。非常实用的是像 sql 这样的查询，SELECT SUM(hours) GROUP BY date但不幸的是，这不是 SQL。

有没有办法通过特定键（在本例中为“日期”）对我的数组进行分组（和排序），或者，如果没有，是否有其他方法可以获得我想要的结果？

编辑

我最近添加了一个关键的“部门”，应该按 to 分组。因此，我不仅要计算“小时”的总和，还要计算“数量”的总和

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1 回答 1

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只需为此创建简单的 foreach 即可。

$arr = array();

$sums = array();
foreach($arr as $k=>$v)
{
     if(!isset($sums[$v['date']][$v['department']]['hours'])) $sums[$v['date']][$v['department']]['hours'] = 0;
     if(!isset($sums[$v['date']][$v['department']]['quantity'])) $sums[$v['date']][$v['department']]['quantity'] = 0;
     $sums[$v['date']][$v['department']]['hours'] += $v['hours'];
     $sums[$v['date']][$v['department']]['quantity'] += $v['quantity'];
}
print_r($sums);

它将创建数组$sum，其中键是您的日期。如果值不存在，它将小时的值添加到 0，否则如果存在，它将添加到现有值。

编辑

适合 OP 需求。

于 2013-05-27T12:21:06.327 回答