我有两节课；
接触
public class Contact : IDisposable
{
private String email;
private String name;
private String address;
private Guid recordId;
public virtual String Id { get; set; }
public virtual String Forename { get; set; }
public virtual String Surname { get; set; }
public virtual String PictureUrl { get; set; }
public virtual String HomeNumber { get; set; }
public virtual String MobileNumber { get; set; }
public virtual DateTime LastUpdated { get; set; }
public virtual Byte[] Picture { get; set; }
[XmlIgnore]
public virtual IList<PostalAddress> PostalAddresses { get; set; }
public virtual String Address
{
get
{
return address;
}
set
{
address = value;
if (PostalAddresses == null) PostalAddresses = new List<PostalAddress>();
if (!String.IsNullOrEmpty(address))
{
PostalAddress postalAddress = new PostalAddress(Address) { OwnedBy = RecordId };
PostalAddresses.Add(postalAddress);
}
}
}
public virtual String Email {
get
{
return email; ;
}
set
{
if (String.IsNullOrEmpty(name))
ExtractName(value);
email = value;
}
}
public virtual String Name
{
get
{
return name;
}
set
{
// if name is actually an email address extract the name part and use that.
if (value.Contains('@'))
ExtractName(value);
else
{
// if name is just some text then use the first word as forename and the rest
// for a surname
name = CultureInfo.CurrentCulture.TextInfo.ToTitleCase(value);
if (name.Contains(' ') && String.IsNullOrEmpty(Forename) && String.IsNullOrEmpty(Surname))
{
String[] splitName = name.Split(' ');
Forename = splitName[0].Trim();
Surname = name.Substring(Forename.Length).Trim(); ;
}
else
{
if (String.IsNullOrEmpty(Forename)) Forename = name;
}
}
}
}
private void ExtractName ( String email )
{
}
/// <summary>
/// Extract numbers from what would be the name
/// </summary>
/// <param name="oldString"></param>
/// <returns></returns>
private String ExtractNumber ( String oldString )
{
}
/// <summary>
/// Extract the forename and surname from an email - replacing .-_ with spaces
/// </summary>
/// <param name="newEmail"></param>
/// <param name="SplitChar"></param>
private void ExtractNameFromEmail(String newEmail,Char SplitChar)
{
}
public virtual Guid Owner { get; set; }
public virtual Guid RecordId
{
get
{
return recordId;
}
set
{
recordId = value;
}
}
public Contact()
{
RecordId = Guid.NewGuid();
Name = String.Empty;
Email = String.Empty;
Forename = String.Empty;
Surname = String.Empty;
Address = String.Empty;
PictureUrl = String.Empty;
PostalAddresses = new List<PostalAddress>();
}
public void Dispose()
{
Name = String.Empty;
Email = String.Empty;
Forename = String.Empty;
Surname = String.Empty;
Address = String.Empty;
PictureUrl = String.Empty;
PostalAddresses = null;
}
}
邮寄地址
public class PostalAddress : IDisposable
{
public PostalAddress()
{
RecordId = Guid.NewGuid();
AddressType = PostalAddressType.HOME;
Address = String.Empty;
Town = String.Empty;
County = String.Empty;
Postcode = String.Empty;
Country = String.Empty;
}
public virtual Guid RecordId { get; set; }
/// <summary>
/// Format the address stored in a String
/// </summary>
/// <param name="Address"></param>
public PostalAddress(String AddressText)
{
}
/// <summary>
/// Type of address
/// </summary>
public virtual PostalAddressType AddressType { get; set; }
/// <summary>
/// Text part of Address
/// </summary>
public virtual String Address { get; set; }
/// <summary>
/// Locality
/// </summary>
public virtual String Locality { get; set; }
/// <summary>
/// Town
/// </summary>
public virtual String Town { get; set; }
/// <summary>
/// County
/// </summary>
public virtual String County { get; set; }
/// <summary>
/// Post or Zip code
/// </summary>
public virtual String Postcode { get; set; }
/// <summary>
/// Country
/// </summary>
public virtual String Country { get; set; }
public virtual Guid OwnedBy { get; set; }
public void Dispose()
{
AddressType = PostalAddressType.HOME;
Address = String.Empty;
Town = String.Empty;
County = String.Empty;
Postcode = String.Empty;
Country = String.Empty;
}
}
以及这两个类的映射
联系方式图
public class ContactMap : ClassMap<Contact>
{
public ContactMap()
{
Table("Contacts");
Id(x => x.RecordId);
HasMany<PostalAddress>(x => x.PostalAddresses)
.KeyColumns.Add("RecordId", mapping => mapping.Name("RecordId"));
Map(x => x.Id);
Map(x => x.Email);
Map(x => x.Forename);
Map(x => x.HomeNumber);
Map(x => x.LastUpdated);
Map(x => x.MobileNumber);
Map(x => x.Owner);
Map(x => x.Picture);
Map(x => x.PictureUrl);
Map(x => x.Surname);
}
}
地址映射
public class AddressMap : ClassMap<PostalAddress>
{
public AddressMap()
{
Table("PostalAddresses");
Id(x => x.RecordId).GeneratedBy.Assigned();
Map(x => x.AddressType);
Map(x => x.Address).Column("AddressText");
Map(x => x.Locality);
Map(x => x.Town);
Map(x => x.County);
Map(x => x.Country);
Map(x => x.Postcode);
References(x => x.OwnedBy)
.Class<Contact>().Columns("OwnedBy");
}
}
以下代码用于保存联系人。
public void Insert ( Contact Contact)
{
ISessionFactory factory = null;
ITransaction transaction = null;
try
{
if (Contact.RecordId == null) Contact.RecordId = Guid.NewGuid();
factory = CreateSessionFactory();
using (var session = factory.OpenSession())
{
transaction = session.BeginTransaction();
if (Contact.PostalAddresses.Count > 0)
session.Save(Contact.PostalAddresses[0]);
session.Save(Contact);
transaction.Commit();
}
}
catch (System.Exception ex)
{
throw ex;
}
}
但是，当我尝试使用以下行保存地址时
Session.Save(Contact.PostalAddresses[0]);
它失败了，但有以下异常
Cloud.BusinessObjects.Contacts.Contact.RecordId 发生异常
和一个内在的例外
对象与目标类型不匹配。
我确定问题出在我映射联系人和地址之间关系的方式上——但对于我的生活来说，我看不到我做错了什么。有什么建议和提前感谢吗？