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一切都适用于这段代码,但我希望有一个从 product.php 返回到类别和子类别的链接。

我有 3 个父类别 page1.php、page2.php 和 page3.php 也适用于那些我有子类别 page1.php?subcat=1,2,3,4 page2.php?subcat=1,2,3,4

这是我使用到 product.php 的 php 代码

if (isset($_GET['id'])) {
$id= $_GET['id'];
$result2 = mysql_query("SELECT * FROM products WHERE id='$id' LIMIT 1");
$count = mysql_num_rows($result2);
if ($count > 0) {
while($row = mysql_fetch_array($result2)){ 
$pid = $row["id"];
$pname = $row["name"];
$pprice = $row["price"];
$pnoncategoryid = $row["noncategoryid"];
$pdesc = $row["desc"];
}

// gjeje emrin e categorise dhe nencategorise
$result3=mysql_query("select * from noncategory WHERE ncid=$pnoncategoryid");
while($row=mysql_fetch_array($result3)){
$noncategoryname = $row["ncname"];
$categoryid = $row["categoryid"];
}

$result4=mysql_query("select * from category WHERE cid=$categoryid");
while($row=mysql_fetch_array($result4)){
$categoryname = $row["cname"];
}
//mbaro

在类别和子类别中,我想要链接:

<h3><?php echo $pname; ?></h3>
<div class="pbr"></div>
<h4>Category:</h4>
<p class="price"><?php echo $categoryname; ?> / <?php echo $noncategoryname; ?></p>
<div class="pbr"></div>
<h4>Description:</h4>
<p class="desc"><?php echo $pdesc; ?></p>
<div class="pbr"></div>
<h4>Price:</h4>
<p class="price"><?php echo $pprice; ?> <?php echo _valuta_ ?></p>

抱歉我的英语不好,希望有人能理解我:))

4

1 回答 1

0

您想将文本转换为超链接。像这样?

<?php echo "<a href='category".$categoryid.".php'>".$categoryname."</a>"; ?> / 
<?php echo "<a href='category".$categoryid.".php?subcat=".$pnoncategoryid."'>".$noncategoryname."</a>"; ?>
于 2012-11-08T22:49:24.897 回答