我有一个用于我构建的私人消息传递系统的 MySQL/PHP 代码。它工作得很好,虽然我对这一切都很陌生,所以很难让消息线程以最新的优先显示。有没有机会提供建议?当前代码如下:
$result = '';
$nowTime = time();
$getmessages = mysql_query("SELECT * FROM messages WHERE msg_to = '$session_memberid' GROUP BY msg_from ORDER BY ID DESC");
while($iamessages = mysql_fetch_array($getmessages))
{
$msg_id = $iamessages['ID'];
$msg_from = $iamessages['msg_from'];
$msg_conversation = $iamessages['conversation'];
$getmsgdata = mysql_query("SELECT * FROM messages WHERE msg_to = '$session_memberid' AND msg_from = '$msg_from' ORDER BY ID DESC LIMIT 1");
while($imsd = mysql_fetch_array($getmsgdata))
{
$msg_message = $imsd['msg_message'];
$msg_time = $imsd['time'];
$msg_read = $imsd['msg_read'];
}
$msg_conversation = suitcrypt($msg_conversation);
if ( $msg_read == 'no' ) { $msgclass = "messagepostunread"; } else { $msgclass = "messagepost"; }
$getfromdata = mysql_query("SELECT FullName, Username, status FROM members WHERE ID = '$msg_from'");
while($ifd = mysql_fetch_array($getfromdata))
{
$msg_from_name = $ifd['FullName'];
$msg_from_username = $ifd['Username'];
$msg_from_status = $ifd['status'];
}
$getfromdata1 = mysql_query("SELECT Link FROM images WHERE MemberID = '$msg_from' AND is_primary = 'yes'");
while($ifd1 = mysql_fetch_array($getfromdata1)) {
$msg_from_img = $ifd1['Link'];
}
$timepass = timing($msg_time);
if ( $timepass == 'data' ) {
$timepass = date("dS M", $msg_time);
}
if ( ( $msg_from_status == 'full' ) || ( $msg_from_status == 'active' ) ) {
$result .= "
<div class=\"$msgclass\" onclick=\"showconversation('$msg_conversation');\">
<img src=\"m/members_image/$msg_from/thumb-$msg_from_img\" class=\"feedpic\" width=\"55\" height=\"55\" /><div class=\"messageposttext\"><a href=\"/$msg_from_username\">$msg_from_name</a>:<div class=\"inboxfeedreply\">Reply · $timepass</div><br />$msg_message</div>
</div>
<div class=\"splittermessages\"></div>
";
}
在消息表中的每个表条目中都有一个“时间”标记。这是时间条目的示例:1367680391。按最新回复优先排序线程的最佳方法是什么?