1

我想做的是让它看起来像这样的java文件

public class test1 {
public static void main ( string[] args ) {
System.out.println( "This is Test 1." );
}
}

并且假设输出具有适当间距和缩进的文本文件。到目前为止，我可以为第一行获得正确的缩进。但是我的第二个 for 循环打印结束括号的空格时遇到问题。结束括号像前 3 行一样向外打印，而不是向内打印。对不起，如果我的变量令人困惑。

到目前为止，这是我的代码

public class JavaJustifier {
public static void main( String[] args ) 
           throws FileNotFoundException {

    for( int i = 1; i < 6; i++ ) {
        justifyJava( "Test" + i + ".java", 
                     "Justified" + i + ".txt", 
                     4 );
    }                
}
public static void justifyJava( String inputFileName,
                                String outputFileName,
                                int tabSize ) 
        throws FileNotFoundException {


    int counter = 0;
    int counter2 = 0;
    int blah = 0;
    File f = new File(inputFileName);
    File p = new File(outputFileName);
    if  (p.exists())
        p.delete();
    Scanner input = new Scanner (f);
    PrintStream name = new PrintStream(new File(outputFileName));

    while (input.hasNextLine()) {
        String line = input.nextLine();
        Scanner lineScan = new Scanner(line);
        if (line.contains("{") == true) {
            name.print("{\r\n");
            counter++;
            for (int i = 1; i <= counter; i++) {
                for (int j = 0; j <= tabSize; j++) {
                    name.print(" ");
                }
            }
            System.out.println(counter);
        } else if (line.contains("}") == true) {
            name.print("\r\n");
            counter--;
            for (int x = 1; x <= counter; x++) {
                for (int y = 1; y <= tabSize; y++) {
                    name.print(" ");
                }
            }
            name.print("}");
            System.out.println(counter);
        } else {
            name.print(line);
        }
    }
}

它给我的是

public class Test1 
{
    public static void main( String[] args ) 
    {
        System.out.println( "This is Test 1." );
}
    }

我想要的是这个

public class Test1 
{
    public static void main( String[] args ) 
    {
        System.out.println( "This is Test 1." );
    }
}
4

1 回答 1

0

好的，我已经重构了一些东西（这是必要的），但它完全按照您的预期工作（AFAIK！）。

这是代码：

public class JavaJustifier {
    static int counter = 0;
    static int tabSize = 4;

    public static void main(String[] args) throws FileNotFoundException {
        justifyJava("Test1.java", "Justified1.txt");
    }

    private static void processLine(PrintStream name, String line) {
        if (line.contains("{")) {
            String preText = line.substring(0, line.indexOf("{"));
            String postText = line.substring(line.indexOf("{") + 1)
                    .replaceAll("\\n", "").replaceAll("\\r\\n", "");
            printSpaces(name);
            name.println(preText);
            printSpaces(name);
            name.println("{");
            counter++;
            processLine(name, postText);

        } else if (line.contains("}")) {
            String preText = line.substring(0, line.indexOf("}"));
            String postText = line.substring(line.indexOf("}") + 1)
                    .replaceAll("\\n", "").replaceAll("\\r\\n", "");
            name.println(preText);
            counter--;
            printSpaces(name);
            name.println("}");
            processLine(name, postText);
        } else {
            if (!line.equals("\r\n") && line.length() != 0) {
                printSpaces(name);
                name.print(line);
            }
        }
    }

    private static void printSpaces(PrintStream p) {
        for (int i = 1; i <= counter; i++) {
            for (int j = 0; j <= tabSize; j++) {
                p.print(" ");
            }
        }
    }

    public static void justifyJava(String inputFileName, String outputFileName)
            throws FileNotFoundException {

        File f = new File(inputFileName);
        File p = new File(outputFileName);
        if (p.exists())
            p.delete();
        Scanner input = new Scanner(f);
        PrintStream name = new PrintStream(new File(outputFileName));

        while (input.hasNextLine()) {
            String line = input.nextLine().trim();
            processLine(name, line);
        }
    }
}
于 2013-05-20T09:32:18.970 回答