2

我希望我的 android 设备连接到 wifi 热点。我创建了一个新的wificonfiguration并将其添加到 中wifimanager，这wificonfiguration有NetworkId。然后我调用该函数wifi.enableNetwork(NetworkId, true).

之后，我认为请求者将通过获取IP地址，身份验证，最后物理连接到热点。那么有没有办法识别wifi是否物理连接？

我更喜欢类似处理程序的方法。

4

4 回答 4

10

你可以试试这个：

ConnectivityManager cm = (ConnectivityManager) getSystemService(CONNECTIVITY_SERVICE);
NetworkInfo wifi = cm.getNetworkInfo(ConnectivityManager.TYPE_WIFI);

if (wifi.isConnected()) {
    // Your code here
}

编辑：更多细节：

BroadcastReceiver在您的清单中注册 a ，如下所示：

<receiver android:name="WifiReceiver">
    <intent-filter>
        <action android:name="android.net.conn.CONNECTIVITY_CHANGE"/>
        <action android:name="android.net.wifi.STATE_CHANGE"/>
    </intent-filter>
</receiver>

然后将上面的代码放在onReceive()接收器的方法上，如下所示：

@Override
public void onReceive(Context context, final Intent intent) {
    ConnectivityManager cm = (ConnectivityManager) getSystemService(CONNECTIVITY_SERVICE);
    NetworkInfo wifi = cm.getNetworkInfo(ConnectivityManager.TYPE_WIFI);

    if (wifi.isConnected()) {
        // Your code here
    }
}
于 2013-05-16T04:50:47.367 回答
6

你可以检查所有的网络。如果您只想要 WIFI，您可以取消检查其他 2 个网络。

public static boolean hasInternetConnection()
{
    ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo wifiNetwork = cm.getNetworkInfo(ConnectivityManager.TYPE_WIFI);
    if (wifiNetwork != null && wifiNetwork.isConnected())
    {
        return true;
    }
    NetworkInfo mobileNetwork = cm.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);
    if (mobileNetwork != null && mobileNetwork.isConnected())
    {
        return true;
    }
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    if (activeNetwork != null && activeNetwork.isConnected())
    {
        return true;
    }
    return false;
}

不要忘记在清单中添加以下内容：

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />
于 2013-05-16T12:18:24.717 回答
2

这可能对您有所帮助。 

public static boolean isInternetAvailable(Context context) {
    boolean haveConnectedWifi = false;
    boolean haveConnectedMobile = false;
    boolean connectionavailable = false;
    ConnectivityManager cm = (ConnectivityManager) context
            .getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo[] netInfo = cm.getAllNetworkInfo();
    NetworkInfo informationabtnet = cm.getActiveNetworkInfo();
    for (NetworkInfo ni : netInfo) {
        try {
            if (ni.getTypeName().equalsIgnoreCase("WIFI"))
                if (ni.isConnected()) haveConnectedWifi = true;
            if (ni.getTypeName().equalsIgnoreCase("MOBILE"))
                if (ni.isConnected()) haveConnectedMobile = true;
            if (informationabtnet.isAvailable()
                && informationabtnet.isConnected())
                connectionavailable = true;
            Log.i("ConnectionAvailable", "" + connectionavailable);
        } catch (Exception e) {
            System.out.println("Inside utils catch clause , exception is"
                + e.toString());
            e.printStackTrace();
        }
    }
    return haveConnectedWifi || haveConnectedMobile;
}
于 2013-05-16T12:10:03.140 回答
0

getNetworkInfo(int) 方法已弃用。你可以应用这样的东西

 ConnectivityManager connectivityManager = (ConnectivityManager) mContext.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = connectivityManager.getActiveNetworkInfo();
    if (activeNetwork != null) { 
        // connected to the internet
        if (activeNetwork.getType() == ConnectivityManager.TYPE_WIFI) {
            // connected to wifi

        } else if (activeNetwork.getType() == ConnectivityManager.TYPE_MOBILE) {
            // connected to the mobile network
        }
    } else {
        // not connected to the internet
    }

另外，请在 AndroidManifest.xml 下添加此权限

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
于 2017-06-12T03:25:01.153 回答