vb.net - 如何从句子中找到确切的单词

Question

在我的窗口应用程序中，我想从句子中找到确切的单词。这两个字段将分别是文本框（单词）和丰富文本框（句子）。

我使用了 Str(i).contains(word) 和 For Each match As Match In Regex.Matches(str(i), word)。

但是这两个没有得到确切的词。例如，Word:ate sentence:parfaite ment aux exigences cre* ate * évolutives du marché d aujourd hui

在上面它获取了 create.but 中的 ate，但我需要只关注 ate 而不是组合。

Answer 1

在您的 Regex.Matches 中，您需要使用 \b 单词边界字符。我刚刚用 C# 编写了一个示例代码，现在我注意到您的问题是针对 VB.NET，所以我将添加两个代码示例：

C＃：

        //Example 1:
        var testString = "parfaite ment aux exigences create évolutives du marché d aujourd hui";
        var pattern = "ate";
        MatchCollection found = Regex.Matches(testString, @"\b" + pattern + @"\b");

        if (found.Count > 0)
        {
            foreach (Match f in found)
            {
                Console.WriteLine("'{0}' found at position {1} in given testString.", f.Value, f.Index);
            }
        }
        else Console.WriteLine("No matches in given testString.");


        //Example 2:
        var testString1 = "parfaite ment aux exigences cre*ate* évolutives du marché d aujourd hui I don't know the language but this: ate and the last one should be found: ate!";
        var pattern1 = "ate";
        MatchCollection found1 = Regex.Matches(testString1, @"\b" + pattern1 + @"\b");

        if (found1.Count > 0)
        {
            foreach (Match f in found1)
            {
                Console.WriteLine("'{0}' found at position {1} in given testString1.", f.Value, f.Index);
            }
        }
        else Console.WriteLine("No matches in given testString1.");

        Console.ReadLine();

VB.NET：

    'Example 1:
    Dim testString = "parfaite ment aux exigences create évolutives du marché d aujourd hui"
    Dim pattern = "ate"
    Dim found As MatchCollection = Regex.Matches(testString, "\b" & pattern & "\b")

    If found.Count > 0 Then
        For Each f In found
            Console.WriteLine("'{0}' found at position {1} in given testString.", f.Value, f.Index)
        Next
    Else
        Console.WriteLine("No matches in given testString.")
    End If

    'Example 2:
    Dim testString1 = "parfaite ment aux exigences cre*ate* évolutives du marché d aujourd hui I don't know the language but this: ate and the last one should be found: ate!"
    Dim pattern1 = "ate"
    Dim found1 As MatchCollection = Regex.Matches(testString1, "\b" & pattern1 & "\b")

    If (found1.Count > 0) Then

        For Each f As Match In found1
            Console.WriteLine("'{0}' found at position {1} in given testString1.", f.Value, f.Index)
        Next
    Else
        Console.WriteLine("No matches in given testString1.")
    End If

    Console.ReadLine()

Answer 2

也许这会有所帮助？

Private Sub SearchForWord()
    Dim SearchString() As String = Split("ate parfaite ment aux exigences cre*ate* évolutives du marché d aujourd hui", " ")
    Dim WordToFind As String = "ate"
    Dim count As Integer = 0
    Dim NumMatches As Integer = 0

    Do Until count = UBound(SearchString)
        If UCase$(WordToFind) = UCase$(SearchString(count)) Then
            NumMatches = NumMatches + 1
        End If
        count = count + 1
    Loop

    Debug.Print(Format(NumMatches))

End Sub