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我有一个关于运算符以及如何重载它们的问题。有一个代码示例，我正在重载operator<<，但它不起作用。我使用了一个类：

class CStudent{ //class for students and their attributes
    int m_id;
    int m_age;
    float m_studyAverage;

    public:

    CStudent(int initId, int initAge, float initStudyAverage): m_id(initId), m_age(initAge), m_studyAverage(initStudyAverage){}

    int changeId(int newId){
        m_id = newId;
        return m_id;
    }
    int increaseAge(){
        m_age++;
        return m_age;
    }
    float changeStudyAverage(float value){
        m_studyAverage += value;
        return m_studyAverage;
    }
    void printDetails(){
        cout << m_id << endl;
        cout << m_age << endl;
        cout << m_studyAverage << endl;
    }

    friend ostream operator<< (ostream stream, const CStudent student);
};

超载：

ostream operator<< (ostream stream, const CStudent student){
    stream << student.m_id << endl;
    stream << student.m_age << endl;
    stream << student.m_studyAverage << endl;
    return stream;
}

并且有主要方法：

int main(){

    CStudent peter(1564212,20,1.1);
    CStudent carl(154624,24,2.6);

    cout << "Before the change" << endl;
    peter.printDetails();
    cout << carl;

    peter.increaseAge(); 
    peter.changeStudyAverage(0.3);
    carl.changeId(221783);
    carl.changeStudyAverage(-1.1);

    cout << "After the change" << endl;
    peter.printDetails();
    cout << carl;

    return 0;
}

哪里有问题？

4

1 回答 1

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这里的问题是您需要了解引用是什么以及 std::ostream 和 std::ostream& 之间的区别。

std::ostream& operator<< (std::ostream& stream, const CStudent& student)

于 2013-05-12T00:49:17.710 回答