1

我有 40 对鸟类,每只雄性和雌性都根据颜色评分。颜色分数是一个分类变量(范围为 1 到 9)。我想绘制男性和女性对颜色组合数量的频率。我必须用每个组合的数量(1/1、1/2、1/3、... 9/7、9/8、9/9)创建一个“表”,然后将其转换为一个名为'颜色计数'。我想在“绘图”中为“cex”参数使用“Colour_Count”来缩放每种颜色组合的大小。由于从表中读取数据的顺序,这不起作用。如何创建具有每种颜色组合频率的矢量来缩放我的绘图点?

请参阅下面的数据和代码:

## Dataset pairs of males and females and their colour classes
Pair_Colours <- structure(list(Male = c(7, 6, 4, 6, 8, 8, 5, 6, 6, 8, 6, 6, 5, 
7, 9, 5, 8, 7, 5, 5, 4, 6, 7, 7, 3, 6, 5, 4, 7, 4, 3, 9, 4, 4, 
4, 4, 9, 6, 6, 6), Female = c(9, 8, 8, 9, 3, 6, 8, 5, 8, 9, 7, 
3, 6, 5, 8, 9, 7, 3, 6, 4, 4, 4, 8, 8, 6, 7, 4, 2, 8, 9, 5, 6, 
8, 8, 4, 4, 5, 9, 7, 8)), .Names = c("Male", "Female"), class = "data.frame", row.names = c(NA, 
40L))

Pair_Colours[] <- as.data.frame(lapply(Pair_Colours, factor, levels=1:9))

## table of pair colour values (colours 1 to 9 - categoricial variable)
table(Pair_Colours$Male, Pair_Colours$Female)

Colour_Count <-  as.vector(table(Pair_Colours$Male, Pair_Colours$Female)) #<- the problem occurs here

## plot results to visisually look for possible assortative mating by colour
op<-par(mfrow=c(1,1), oma=c(2,4,0,0), mar=c(4,5,1,2), pty = "s")
plot(1,1, xlim = c(1, 9), ylim = c(1, 9), type="n", xaxt = "n", yaxt = "n", las=1, bty="n", cex.lab = 1.75, cex.axis = 1.5, main = NULL, xlab = "Male Colour", ylab = "Female Colour", pty = "s")
axis(1, at = seq(1, 9, by = 1), labels = T, cex.lab = 1.5, cex.axis = 1.5, tick = TRUE, tck = -0.015, lwd = 1.25, lwd.ticks = 1.25)
axis(2, at = seq(1, 9, by = 1), labels = T, cex.lab = 1.5, cex.axis = 1.5, tick = TRUE, tck = -0.015, lwd = 1.25, lwd.ticks = 1.25, las =2)
points(Pair_Colours$Male, Pair_Colours$Female, pch = 21, cex = Colour_Count, bg = "darkgray", col = "black", lwd = 1)
4

1 回答 1

4

您可以ddply()使用库 plyr 的功能汇总您的数据,然后使用这个新的数据框来绘制您的数据。计数在V1新数据框的列中。

library(plyr)
df<-ddply(Pair_Colours,.(Male,Female),nrow)
df
   Male Female V1
1     3      5  1
2     3      6  1
3     4      2  1
4     4      4  3

points(df$Male, df$Female, pch = 21, cex = df$V1, 
               bg = "darkgray", col = "black", lwd = 1)

更新 - 使用聚合的解决方案

其他可能性是使用 function aggregate()。首先,添加N仅包含值 1 的新列。然后为每个和组合添加aggregate()总和值。NMaleFemale

Pair_Colours$N<-1
aggregate(N~Male+Female,data=Pair_Colours,FUN=sum)

   Male Female N
1     4      2 1
2     6      3 1
3     7      3 1
4     8      3 1
5     4      4 3

在此处输入图像描述

于 2013-05-04T15:28:25.573 回答