java - 如何使用 TestNG DataProvider 传递 > 10 个参数？

Question

我需要将 10 多个参数传递给 TestNG Dataprovider，并且代码看起来像这样......

@Test (dataProvider = "Dataprovider1")
public void testScenario1(String data1, String data2,
                          String data3, String data4,
                          String data5 //...
            ) throws Exception {
    System.out.println(data1+"---------------- "+data2+" ---------------   "+data3+" .. so on");
}

谁能告诉我如果我们需要传递超过 10 个参数，我们应该采用什么方法@DataProvider？有没有其他方法来声明测试方法的参数？

Answer 1

如果您有相同类型的参数，那么您可以在方法参数中作为数组传递。

@Test (dataProvider = "Dataprovider1")
public void testScenario1(String args [])
            ) throws Exception {
    System.out.println(args[0]+"---------------- "+args[1]+" ---------------   "+args[3]+" .. so on");
}

此外，如果您有不同类型的参数字段，那么您可以在辅助类的帮助下对其进行处理，然后在参数中传递此类的引用。例如：

class Helper {
  String data1;
  String data2;
  String data3;
  Long data4;
  int data5;
  flot data6;
 -----so on------
 ----getter setter and constructor----
}

你的测试班

class Test {
@DataProvider(name="Dataprovider1")
public static Object[][] testData() {
    return new Object[][] {
            { new Helper("hey", "you", "guys" ..... another constructor parameters..) } }
    };

}

@Test (dataProvider = "Dataprovider1")
public void testScenario1(Helper helper) throws Exception {
    System.out.println(helper.data1+"---------------- "+helper.data2+" ---------------   "+helper.data3+" .. so on");
}
}

Answer 2

You can set the dataprovider to be an array of Object and use ArrayList> to have your parameters in key value pairs.

@DataProvider
public Object[][] getTestData()
{
    List<HashMap<String, String>> arrayMapList = new ArrayList<HashMap<String, String>>();
    HashMap<String, String> hashMapItems = new HashMap<String, String>();

    //use a loop to fill in all the parameter name and value pairs
    hashMapItems.put("parameterName1", "parameterValue");
    hashMapItems.put("parameterName2", "parameterValue");
    //--------------More put statements here------
    //finally add hash map to the list
    arrayMapList.add(hashMapItems);

    //Iterate the array list and store each HashMap object in an object array. First dimension is the iterator value.
    Object [][] hashMapObj = new Object [arrayMapList.size()][1];

    for(int i=0; i<arrayMapList.size() ; i++) {
        hashMapObj[i][0] = arrayMapList(i);
    }

    return hashMapObj;
}

for each hashmap value in the array list, the test method will be run with its own set of parameters

@Test (dataProvider = "getTestData", enabled = true)
public void testDataRead(HashMap<String,String> hashMapValue)
{
    System.out.println(hashMapValue.get(parameterNameKey));  //parameter 1
    System.out.println(hashMapValue.get(parameterNameKey));  //parameter 2
}

Answer 3

执行此操作时，DataProvider 会以一种令人讨厌的语法结束。这是一个例子：

@DataProvider(name="objectTestData")
public static Object[][] objectTestData() {
    return new Object[][] {
            { new TestData("hey", "you", "guys") },
            { new TestData("Sloth", "Baby", "Ruth") },
            { new TestData("foo", "bar", "baz") }
    };
}

@Test(dataProvider="objectTestData")
public void testScenario1(TestData data) {
    System.out.println(data.get(0) + "..." + data.get(1) + "..." + data.get(2));
}

static class TestData {
    public String[] items;

    public TestData(String... items) {
        this.items = items; // should probably make a defensive copy
    }

    public String get(int x) {
        return items[x];
    }
}

或者，您可以更改 TestData 构造函数以将内容放入单独的命名方法中。（例如，如果您正在测试地址数据，可能有 getName、getAddress、getCity。）

Answer 4

使用Mapin@DataProvider插入许多带值的参数，并返回包含地图的对象，如下所示：

@DataProvider
public static Object[][]Dataprovider1(){
    Map<String, String> map = new HashMap<String, String>();
    map.put("data1", "value1");
    map.put("data2", "value2");
    ....
    map.put("data10", "value10");
    return new Object[][] {
        {map}
    };
}

在@test您可以通过添加Map也作为子参数来获取数据：

@Test(dataProvider = "Dataprovider1")
public void testScenario1(Map<String, String> data) {
    System.out.println(data.get("data1"));
    System.out.println(data.get("data2"));
    ....
}

它将产生：

value1
value2
....