android - 在 ListView Android 中创建不同数量的项目

Question

在此适配器中，您必须将项目填充到已在布局中创建的 ID。

当我的导入列表中的每个项目对于每个列表行都有不同数量的图像或文本时，如何继续在此适配器内创建新的 Imageview（或其他）？

例子：

我想根据每个项目在黑/白框所在的位置填写 X 张图片。

public class CustomBaseAdapter extends BaseAdapter {
        Context context;
        List<RowItem> rowItems;

        public CustomBaseAdapter(Context context, List<RowItem> items) {
            this.context = context;
            this.rowItems = items;
        }

        /*private view holder class*/
        private class ViewHolder {
            ImageView imageView;
            TextView txtTitle;
            TextView txtDesc;
        }

        public View getView(int position, View convertView, ViewGroup parent) {
            ViewHolder holder = null;

            LayoutInflater mInflater = (LayoutInflater)
                context.getSystemService(Activity.LAYOUT_INFLATER_SERVICE);
            if (convertView == null) {
                convertView = mInflater.inflate(R.layout.list_item, null);
                holder = new ViewHolder();
                holder.txtDesc = (TextView) convertView.findViewById(R.id.desc);
                holder.txtTitle = (TextView) convertView.findViewById(R.id.title);
                holder.imageView = (ImageView) convertView.findViewById(R.id.icon);
                convertView.setTag(holder);
            }
            else {
                holder = (ViewHolder) convertView.getTag();
            }

            RowItem rowItem = (RowItem) getItem(position);

            holder.txtDesc.setText(rowItem.getDesc());
            holder.txtTitle.setText(rowItem.getTitle());
            holder.imageView.setImageResource(rowItem.getImageId());

            return convertView;
        }

        @Override
        public int getCount() {
            return rowItems.size();
        }

        @Override
        public Object getItem(int position) {
            return rowItems.get(position);
        }

        @Override
        public long getItemId(int position) {
            return rowItems.indexOf(getItem(position));
        }
    }