0

在我的应用程序中，我有活动 A 和 B。在活动 B 中，我想检查应用程序的空闲状态，如果用户没有交互或最小化应用程序几分钟意味着如何将其恢复为活动 AI 不知道如何找出应用程序的空闲时间。任何人都可以帮助我解决这个问题。

4

2 回答 2

3

在 iOS 中：

1)Create a new file -> Objective-C class -> type in a name (in my case TIMERUIApplication) and change the subclass to UIApplication. You may have to manually type this in the subclass field. You should now have the appropriate .h and .m files.

2) 在 .h 文件中

#import <Foundation/Foundation.h>

//the length of time before your application "times out". This number actually represents seconds, so we'll have to multiple it by 60 in the .m file
#define kApplicationTimeoutInMinutes 5
#define kMaxIdleTimeSeconds 60.0

//the notification your AppDelegate needs to watch for in order to know that it has indeed "timed out"
#define kApplicationDidTimeoutNotification @"AppTimeOut"

@interface TIMERUIApplication : UIApplication
{
    NSTimer     *myidleTimer;
}

-(void)resetIdleTimer;

@end

3) .m 文件

#import "TIMERUIApplication.h"

@implementation TIMERUIApplication

//here we are listening for any touch. If the screen receives touch, the timer is reset
-(void)sendEvent:(UIEvent *)event
{
    [super sendEvent:event];

    if (!myidleTimer)
    {
        [self resetIdleTimer];
    }

    NSSet *allTouches = [event allTouches];
    if ([allTouches count] > 0)
    {
        UITouchPhase phase = ((UITouch *)[allTouches anyObject]).phase;
        if (phase == UITouchPhaseBegan)
        {
            [self resetIdleTimer];
        }

    }
}
//as labeled...reset the timer
-(void)resetIdleTimer
{
    if (myidleTimer)
    {
        [myidleTimer invalidate];
    }
    //convert the wait period into minutes rather than seconds
    int timeout = kApplicationTimeoutInMinutes * 60;
    myidleTimer = [NSTimer scheduledTimerWithTimeInterval:timeout target:self selector:@selector(idleTimerExceeded) userInfo:nil repeats:NO];

}
//if the timer reaches the limit as defined in kApplicationTimeoutInMinutes, post this notification
-(void)idleTimerExceeded
{
    [[NSNotificationCenter defaultCenter] postNotificationName:kApplicationDidTimeoutNotification object:nil];
}


@end

4）在main.m中

#import <UIKit/UIKit.h>

#import "AppDelegate.h"
#import "TIMERUIApplication.h"

int main(int argc, char *argv[])
{
    @autoreleasepool {
        return UIApplicationMain(argc, argv, NSStringFromClass([TIMERUIApplication class]), NSStringFromClass([AppDelegate class]));
    }
}

5）在appdelegate中

#import "AppDelegate.h"
#import "TIMERUIApplication.h"

@implementation AppDelegate

@synthesize window = _window;

-(BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions 
{      
    [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(applicationDidTimeout:) name:kApplicationDidTimeoutNotification object:nil];

    return YES;
}

-(void)applicationDidTimeout:(NSNotification *) notif
{
    //revert to Activity A
}

希望这可以帮助....

于 2013-04-27T07:46:47.353 回答
0

您的问题是关于 iOS 还是 Android？

在 iOS 上，在您的 AppDelegate 中，您的应用程序调用的方法将进入后台和前台，您可以存储每个时刻的时间戳并计算时间。

此外，您还拥有 applicationState（查看 UIApplication 文档），使用此属性您可以知道您的应用程序是处于活动状态、后台运行还是非活动状态。

Sunny 回答的 setIdleTimerDisabled 方法用于激活/停用计时器，当您在屏幕上停留几秒/分钟时关闭屏幕。手电筒应用程序或使用加速度计玩的游戏很常见。

我不知道安卓。

于 2013-04-27T07:52:40.613 回答