我有一个有序故事的索引:
{
index: ["storyA", "storyB", "storyC"]
}
我想获取引用的故事并将其传递给 angularFireCollection
{
index: ["storyA", "storyB", "storyC"],
stories: {
"storyA" : {},
"storyB" : {},
"storyC" : {},
"storyD" : {},
"storyE" : {}
},
}
这是来自 angularfire 的示例。这将获得所有故事,而不仅仅是索引中的故事。如何仅获取索引中的那些?
app.controller('stories', ['$scope', '$timeout', 'angularFireCollection',
function($scope, $timeout, angularFireCollection) {
var url = 'https://example.firebaseio.com/stories';
$scope.stories = angularFireCollection(url);
}
]);