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在过程调用的函数中使用两个 sum() 时，我遇到了一个问题。输入的结果是分开的。以下表格，功能和程序是我尝试过的。PS - 当有一个 sum(x) 时它工作正常。 

 DROP TABLE MATCH;
    CREATE TABLE MATCH 
       (M_ID VARCHAR2 (4) NOT NULL,
        HT_ID VARCHAR2 (4),
        AT_ID VARCHAR2 (4),
        P_F NUMBER (3),
      P_A NUMBER (3));


INSERT INTO MATCH VALUES
('M01','T1', 'T2',  2, 0);

INSERT INTO MATCH VALUES
('M02','T1', 'T2',  1, 1);

INSERT INTO MATCH VALUES
('M03','T1', 'T2',  0, 2);

INSERT INTO MATCH VALUES
('M04','T1', 'T2', 0, 2);

INSERT INTO MATCH VALUES
('M05','T2', 'T1', 2, 0);

INSERT INTO MATCH VALUES
('M06','T2', 'T1',  0, 2);

INSERT INTO MATCH VALUES
('M07','T2', 'T1',  1, 2);

INSERT INTO MATCH VALUES
('M08','T2', 'T1',  0, 2);

临时表（将存储结果）：

DROP TABLE RESULTS;
CREATE GLOBAL TEMPORARY TABLE RESULTS
(ht_id varchar2 (5),
 FINAL NUMBER (2))
 ON COMMIT PRESERVE ROWS;

 insert into RESULTS values('T1', NULL);
 insert into RESULTS values('T2', NULL);
 insert into RESULTS values('T3', NULL);
 insert into RESULTS values('T4', NULL);
 insert into RESULTS values('T5', NULL);

我申请的查询：

select
sum(case when HT_ID='T1' then P_F else 0 end) +
sum(case when AT_ID='T1' then P_A else 0 end)
from match;

返回 9 的结果，我在一个函数中应用了选择查询，并创建了一个过程来调用该函数并将结果存储在一个临时表中。尽管在函数中完成的求和结果是分开的（例如，T1 为 6，T2 为 3，尽管仅 T1 应该有 9 个点）。

HT_ID      FINAL
----- ----------
T1             3
T2             6
T3             0
T4             0
T5             0

如何保留与查询相同的结果并将它们输入到临时表中？如下所示：

HT_ID      FINAL
----- ----------
T1             9
T2             0
T3             0
T4             0
T5             0

这是我在功能和程序方面尝试过的：

 drop function RESULTSFINAL;
 CREATE OR REPLACE FUNCTION RESULTSFINAL(i_HT_ID RESULTS.HT_ID%TYPE)

 RETURN VARCHAR2
 IS

 v_RESULTS_FINAL  RESULTS.FINAL%TYPE;


BEGIN
 select sum(case when HT_ID='T1' then P_F else 0 end)+ sum(case when AT_ID='T1' then    P_A else 0 end)
 INTO v_RESULTS_FINAL
 FROM MATCH
 WHERE HT_ID = i_HT_ID;

 IF v_RESULTS_FINAL IS NULL THEN
  v_RESULTS_FINAL := 0;
END IF;
RETURN v_RESULTS_FINAL;
END;
/

步骤：

    CREATE OR REPLACE PROCEDURE FINALSCORES
    AS

    CURSOR c_RESULTS
    IS

     SELECT HT_ID
     FROM RESULTS;


    v_HT_ID  RESULTS.HT_ID%TYPE;
    v_RESULTS_FINAL  RESULTS.FINAL%TYPE;

    BEGIN  

    OPEN c_RESULTS;

     LOOP

    FETCH c_RESULTS INTO v_HT_ID;

    EXIT WHEN c_RESULTS%NOTFOUND;

     v_RESULTS_FINAL := RESULTSFINAL(v_HT_ID);

     UPDATE RESULTS
     SET FINAL = v_RESULTS_FINAL
     WHERE HT_ID = v_HT_ID;


   END LOOP;
   CLOSE c_RESULTS;

   END;
    /

执行最终分数；

提前致谢。

4

2 回答 2

1 
select 
  sum(case when HT_ID=i_HT_ID then P_F else 0 end)
  + sum(case when AT_ID=i_HT_ID then P_A else 0 end)
INTO v_RESULTS_FINAL
FROM MATCH;
于 2013-04-25T17:48:42.800 回答
1

您也可以使用 DECODE 执行相同的操作，如下所示：

CREATE OR REPLACE FUNCTION RESULTSFINAL(i_HT_ID RESULTS.HT_ID%TYPE)
 RETURN VARCHAR2
IS

    v_RESULTS_FINAL  RESULTS.FINAL%TYPE;
BEGIN

      select sum(decode(HT_ID,i_HT_ID,P_F,
                              decode(AT_ID,i_HT_ID,P_A,0)))
                into v_RESULTS_FINAL
      from match;

      IF v_RESULTS_FINAL IS NULL THEN
          v_RESULTS_FINAL := 0;
      END IF;

      RETURN v_RESULTS_FINAL;
END;
/
于 2013-04-25T18:33:22.907 回答