0

我有一个表单，并向其中添加动态字段。添加字段后，我想通过以下方式增强名称属性：

<form id="workshops" action="" method="post">
  <input type="hidden" value="1" name="form-0-Workshops">
  <input type="hidden" value="morning" name="form-0-Day">
  <input type="hidden" value="3" name="form-0-Workshops">
  <input type="hidden" value="evening" name="form-0-Day">
  <input type="hidden" value="3" name="form-0-Workshops">
  <input type="hidden" value="morning" name="form-0-Day">
</form>

变成：

<form id="workshops" action="" method="post">
  <input type="hidden" value="1" name="form-0-Workshops">
  <input type="hidden" value="morning" name="form-0-Day">
  <input type="hidden" value="3" name="form-1-Workshops">
  <input type="hidden" value="evening" name="form-1-Day">
  <input type="hidden" value="3" name="form-2-Workshops">
  <input type="hidden" value="morning" name="form-2-Day">
</form>

我有这个开始，但我没有取得任何进展......

var forms = $('form#workshops input[name$="Workshops"]');

for (var i=0, formCount=forms.length; i<formCount; i++){
    $('form#workshops input[name$="Workshops"]').each(function() {
        //$(this) seems to be empty    
    });
}
4

4 回答 4

1

尝试使用这个：

// Get all the forms inputs
var $forms = $('form#workshops input[name$="Workshops"]');

// Loop through each form inputs
$forms.each(function () {
    console.log($(this));
});
于 2013-04-23T13:07:51.133 回答
0

也许只是尝试： 

$('#workshops input[name$="Workshops"]').each(function() { /*...*/ });
于 2013-04-23T13:09:16.113 回答
0

您的代码不断在循环内重新选择事物。没有意义。

充分利用每个优势，它为您提供索引，因此无需执行 for 循环。.

function rename (i) {
    var parts = this.name.split("-");
    parts[1] = i;
    this.name = parts.join("-");
}

var form = $("#workshops");
form.find('input[name$="Workshops"]').each(rename);
form.find('input[name$="Day"]').each(rename);
于 2013-04-23T13:20:56.573 回答
0

请尝试以下代码：

var forms_input = $('form#workshops input[name *="Workshops"]');

forms_input.each(function() {
    console.log($(this))
});
于 2013-04-23T13:31:45.260 回答