1

我有一个这样的选择倍数的表格：

<select name="states[]" size="5" multiple>
    <option value="2">state 1</option>
    <option value="3">state 2</option>
    <option value="4">state 3</option>
    <option value="5">state 4</option>
    <option value="6">state 5</option>
</select>

我希望有可能选择多个状态，然后对我的数据库进行查询并显示所选每个状态的描述。

所以这就是我必须使用 PHP 和 MySQL 进行查询的内容：

$state = $_POST['states'];
$data = mysql_query("SELECT * from states WHERE id_state = '$state'",$db); 

while($row = mysql_fetch_array($data)){
    $result=$row['description'];
}

echo $result;

我有那个代码，它没有显示任何东西。

我该如何解决这个问题？

4

5 回答 5

7

尝试这个

$state = $_POST['states']; // return Array
$count_states = count( $state );

if( $count_states > 0) {
    $states = implode( ',', $state);
    $data = mysql_query("SELECT * from states WHERE id_state IN ($states)",$db); 

    while($row = mysql_fetch_array($data)){
       echo $row['description'];
    }
}
于 2013-04-23T02:15:22.813 回答
1

$_POST['states']包含一个包含所选状态的所有 ID 的数组。

当然，您可以为每个发布的 state_id 查询您的数据库，但是更好（更快）的方式是进行如下查询并且只使用一个查询：

SELECT description FROM states WHERE id_state=1 OR id_state=2 etc etc

这也可能是开始使用像PDO这样的数据库抽象层的好点。由于发布状态的数量是可变的，我们需要使语句也可变：

// The [connection setup][2] by PDO is done in $conn, with some proper exception handlers
// e.g. $conn = new PDO('mysql:host=localhost;dbname=test', $user, $pass);

// Fill an array with count() number of elements with value 'id_state=?'
$place_holders = array_fill(0, count($_POST['state']), 'id_state= ?');

//implode the array 
$place_holders = implode(' OR ', $place_holders);

// prepare the query
$st = $conn->prepare("SELECT description FROM state WHERE $place_holders");

// execute to above prepared query with the $_POSTED states
$st->execute($_POST['state']);

// traverse the result
foreach($st->fetchAll() AS $r){
     // do some magic
}
于 2013-04-23T02:22:26.087 回答
1

这将需要一个简单foreach的遍历数组并根据每个值获取结果，

foreach($_POST['states'] as $state) {
    $data = mysql_query("SELECT * from states WHERE id_state = '$state'",$db);
    $row = mysql_fetch_array($data);
    echo $row['description'];
}

另外，由于您没有以某种方式保护您的查询，并且使用的是自 PHP 5.5.0 起已弃用的mySQL ，我建议您查看PDO或mySQLi Prepared statements

于 2013-04-23T02:11:58.827 回答
0

您可以通过遍历数组来构建字符串：

$state = "";

foreach($_POST['states'] AS $s)
{
    // Sanitize $s here
    $state .= "`id_state` = " . $s . " OR";
}

if($state)
{
    $state = substr($state, 0, -3);

    $data = mysql_query("SELECT * from states WHERE $state",$db); 

    while($row = mysql_fetch_array($data)){
        echo $row['description'];
    }
}

当然，您应该使用MySQLi或PDO之类的东西来处理数据库交互。他们将有办法轻松清理输入，因此您可以避免明显的SQL 注入。

泰米尔语也有一个很好的 IN 选择方法。这只是一种选择。

于 2013-04-23T02:14:48.960 回答
0 
Example (pages for edit):

//On select_multiple.php (Form):

<?php
//Conn
include('incl_config.php');

//Multiple data to bring
$sql = " select COD_DXS,VALOR_DXS from hc_dxsindromico where ESTADO_DXS='1' ";
$result=@mysql_query($sql);       
?>

//In the form select:
<select  multiple="multiple" size="7"  name="dxsindromico[]"> //look yes or yes brackets []
    <option value="" selected="selected">Choose one or more options</option>
        <?php
        while($row=mysql_fetch_array($result)){
    ?>
        <option value="<?php echo $row['COD_DXS']; ?>" style="color:#F00;"><?php echo $row['VALOR_DXS'];?></option> 
        <?php } ?>  
</select>

//////////// On grabar_mtr.php ///////////////

<?php
include('incl_config.php');
/*Multiple selection form in HTML5, PHP and Bootstraps
Created by: www.nycsoluciones.com
Version: 1.1*/

//we use a foreach to traverse the array (values of our select and save them in the table dxsindromico_data)

if(isset($_POST['dxsindromico'])){
    foreach( $_POST['dxsindromico'] as $insertar ) {
        //echo $insertar;
        $sqli="insert into dxsindromico_data(DXSINDROMICO_HC) values('$insertar')";
        //echo $sqli;
        //exit;
        $resulti=mysql_query($sqli);
    } 
} else{
    foreach( $_POST['dxsindromico'] as $insertar ) {
        //echo $insertar;
        $sqli="insert into dxsindromico_data(DXSINDROMICO_HC) values('$insertar')";
        $resulti=mysql_query($sqli);
    } 
}
?>
于 2018-01-25T05:14:50.693 回答