0

我有一个具有多个同名输入的表单，从而生成一个数组。我想将此$_POST数组传递给一个函数，该函数将处理该数组并将其保存到数据库中。

我之前在不使用函数的情况下没有任何问题，但现在我想将它全部包含在一个漂亮的整洁函数调用中，它不会这样做，我不知道为什么？

有问题的输入/后变量被命名option[]并作为$_POST['option']. 这是功能：

function newVariant($name, $option) {
global $db;
global $table_prefix;
$table = $table_prefix . "variants";

$query = $db->prepare("INSERT INTO $table(name) VALUES(:name)");
$query->bindParam(":name", $name);

if (!$query->execute()) {
    die(showMessage("Error!","There has been a problem saving your variant. Please try again or contact technical support if the problem persists.",""));
    }

$variant_id = $db->lastInsertId('id');

for($i = 0; $i < count($option); $i++) {
   if($option[$i] != "") {

      $table2 = $table_prefix . "variant_items";
      $query2 = $db->prepare("INSERT INTO $table2(variant, option) VALUES(:variant, :option)");
      $query2->bindParam(":variant", $variant_id);
      $query2->bindParam(":option", $option[$i]);

      if (!$query2->execute()) {
         die(showMessage("Error!","There has been a problem saving your variant. Please try again or contact technical support if the problem persists.",""));
      }
   }
}

$redirect = renderLink("/beyond/?act=admin&sub=variants", "true");
showMessage("Saving variant...<META HTTP-EQUIV=\"Refresh\" Content=\"1; URL=$redirect\">","","");
}

这是我在日志中遇到的错误：

PHP Fatal error:  Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'option) VALUES(?, ?)' at line 1' in /Users/adampcollings/Sites/Hot Mint Development/beyond/php/functions/product.php:131
Stack trace:
#0 /Users/adampcollings/Sites/Hot Mint Development/beyond/php/functions/product.php(131): PDO->prepare('INSERT INTO bb_...')
#1 /Users/adampcollings/Sites/Hot Mint Development/beyond/html/admin/new-variant.php(5): newVariant('Test', Array)
#2 /Users/adampcollings/Sites/Hot Mint Development/beyond/php/html.php(19): include('/Users/adampcol...')
#3 /Users/adampcollings/Sites/Hot Mint Development/beyond/html/admin.php(10): subElement('admin', 'new-variant')
#4 /Users/adampcollings/Sites/Hot Mint Development/beyond/php/html.php(8): include('/Users/adampcol...')
#5 /Users/adampcollings/Sites/Hot Mint Development/beyond/index.php(14): siteElement('a in /Users/adampcollings/Sites/Hot Mint Development/beyond/php/functions/product.php on line 131
4

1 回答 1

2

根据上面的评论线程，您应该尝试几件事。

首先，在调试应用程序时始终启用错误报告。要在您的脚本中执行此操作，请添加：

error_reporting(E_ALL);

到脚本的顶部。

其次，确保$options包含您期望的数据。在代码的某处，添加以下行：

var_dump($options);

这将向您显示$options. 如果它不包含您期望的值，请检查您的提交过程。

最后，如果$options包含预期的数据，请检查您的表结构以确保您的查询匹配并插入正确的值。

编辑：在您发布 MySQL 错误后，我交叉检查了MySQL Reserved Words list。“选项”一词在列表中。因此，查询失败，因为该词未被识别为列名。尝试用反引号包围列名：

$query2 = $db->prepare("INSERT INTO $table2(`variant`, `option`)...
于 2013-04-22T15:59:48.127 回答