python - 如何加速python的“乌龟”功能并在最后停止冻结

Question

我用python写了一个turtle程序，但是有两个问题。

1. 对于较大的数字来说它太慢了，我想知道如何加快海龟的速度。
2. 它在完成后冻结，单击时显示“没有响应”

到目前为止，这是我的代码：

import turtle

#Takes user input to decide how many squares are needed
f=int(input("How many squares do you want?"))
c=int(input("What colour would you like? red = 1, blue = 2 and green =3"))
n=int(input("What background colour would you like? red = 1, blue = 2 and green =3"))

i=1

x=65

#Draws the desired number of squares.
while i < f:
    i=i+1
    x=x*1.05
    print ("minimise this window ASAP")
    if c==1:
        turtle.pencolor("red")
    elif c==2:
        turtle.pencolor("blue")
    elif c==3:
        turtle.pencolor("green")
    else:
        turtle.pencolor("black")
    if n==1:
        turtle.fillcolor("red")
    elif n==2:
        turtle.fillcolor("blue")
    elif n==3:
        turtle.fillcolor("green")
    else:
        turtle.fillcolor("white")
    turtle.bk(x)
    turtle.rt(90)
    turtle.bk(x)
    turtle.rt(90)
    turtle.bk(x)
    turtle.rt(90)
    turtle.bk(x)
    turtle.rt(90)
    turtle.up()
    turtle.rt(9)
    turtle.down()

顺便说一句：我在 3.2 版！

Answer 1

1. 设置turtle.speed()为fastest。
2. 使用该turtle.mainloop()功能无需刷新屏幕即可工作。
3. 禁用屏幕刷新，turtle.tracer(0, 0)然后在最后执行turtle.update()

Answer 2

Python 乌龟运行非常缓慢，因为每次对乌龟进行修改后都会执行屏幕刷新。

您可以禁用屏幕刷新，直到所有工作完成，然后绘制屏幕，​​它会消除毫秒延迟，因为屏幕会疯狂地尝试从每个海龟变化中更新屏幕。

例如：

import turtle
import random
import time
screen = turtle.Screen()

turtlepower = []

turtle.tracer(0, 0)
for i in range(1000):
    t = turtle.Turtle()
    t.goto(random.random()*500, random.random()*1000)
    turtlepower.append(t)

for i in range(1000):
    turtle.stamp()

turtle.update()

time.sleep(3)

此代码在随机位置生成一千只海龟，并在大约 200 毫秒内显示图片。

如果您没有使用turtle.tracer(0, 0)命令禁用屏幕刷新，它会尝试刷新屏幕 3000 次需要几分钟。

https://docs.python.org/2/library/turtle.html#turtle.delay

Answer 3

作为参考，乌龟速度慢是一个存在的问题。即使将速度设置为最大，乌龟在分形之类的东西上也可能需要很长时间。Nick ODell 在这里重新实现了海龟的速度：隐藏海龟窗口？

import math

class UndrawnTurtle():
def __init__(self):
    self.x, self.y, self.angle = 0.0, 0.0, 0.0
    self.pointsVisited = []
    self._visit()

def position(self):
    return self.x, self.y

def xcor(self):
    return self.x

def ycor(self):
    return self.y

def forward(self, distance):
    angle_radians = math.radians(self.angle)

    self.x += math.cos(angle_radians) * distance
    self.y += math.sin(angle_radians) * distance

    self._visit()

def backward(self, distance):
    self.forward(-distance)

def right(self, angle):
    self.angle -= angle

def left(self, angle):
    self.angle += angle

def setpos(self, x, y = None):
    """Can be passed either a tuple or two numbers."""
    if y == None:
        self.x = x[0]
        self.y = x[1]
    else:
        self.x = x
        self.y = y
    self._visit()

def _visit(self):
    """Add point to the list of points gone to by the turtle."""
    self.pointsVisited.append(self.position())

# Now for some aliases. Everything that's implemented in this class
# should be aliased the same way as the actual api.
fd = forward
bk = backward
back = backward
rt = right
lt = left
setposition = setpos
goto = setpos
pos = position

ut = UndrawnTurtle()

Answer 4

我无法真正解决速度问题，但可以通过turtle. done()在文件末尾使用来防止冻结，谢谢