10

我想像这样使用这样的方式将请求从Servlet转发到ActionRequestDispacher

RequestDispatcher dispatcher=request.getRequestDispatcher("hello.action");
dispatcher.include(request, response);

它不工作。我该如何解决这个问题?

4

2 回答 2

10

为了做到这一点,您可能还需要将过滤器设置为在 FORWARD 上运行(并且如您的代码所示,包括,尽管您声明您想要一个 FORWARD):

<filter-mapping>
  <filter-name>struts2</filter-name>
  <url-pattern>/*</url-pattern>
  <dispatcher>REQUEST</dispatcher> 
  <dispatcher>FORWARD</dispatcher>
  <dispatcher>INCLUDE</dispatcher> <!-- If you want includes as well -->
</filter-mapping>
于 2013-04-20T18:30:40.147 回答
9

使用 servlet 中的代码

getServletContext().getRequestDispatcher("/hello.action").forward(request, response);

您还配置了 struts2 过滤器以接受转发请求

<filter>
  <filter-name>struts2</filter-name>
  <filter-class>
    org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
  </filter-class>
</filter>
<filter-mapping>
  <filter-name>struts2</filter-name>
  <url-pattern>/*</url-pattern>
  <dispatcher>REQUEST</dispatcher>
  <dispatcher>FORWARD</dispatcher>
</filter-mapping>
于 2013-04-20T11:47:32.540 回答