iphone - 以编程方式将 UILabel 彼此相邻放置

Question

我有三个不同宽度的 UILabel，我想将它们并排排列。如何获取更新框架的 X 值？

这是我所拥有的：

UILabel *contractLabel = (UILabel *) [cell viewWithTag:200];
contractLabel.text = [board getDisplayLevel];

UILabel *contractSuit = (UILabel *) [cell viewWithTag:201];
contractSuit.text = [board getDisplayStrain];
contractSuit.textColor = [board getDisplayStrainColor];
contractSuit.hidden = NO;
contractSuit.frame = CGRectMake(contractSuit.frame.origin.x = contractLabel.frame.origin.x + contractLabel.bounds.size.width + 3, contractSuit.frame.origin.y, contractSuit.frame.size.width, contractSuit.frame.size.height); // line 121

UILabel *contractTail = (UILabel *) [cell viewWithTag:202];
contractTail.text = [board getDisplayContract];
contractTail.hidden = NO;
contractTail.frame.origin.x = contractSuit.frame.origin.x + contractSuit.bounds.size.width + 3; // line 127

对框架的两个分配都失败了：

ViewBoards_ViewController.m:121: error: lvalue required as left operand of assignment
ViewBoards_ViewController.m:127: error: lvalue required as left operand of assignment

我究竟做错了什么？

Answer 1

你有一个简单的错字

contractSuit.frame = CGRectMake(contractSuit.frame.origin.x = contractLabel.frame.origin.x + contractLabel.bounds.size.width + 3, contractSuit.frame.origin.y, contractSuit.frame.size.width, contractSuit.frame.size.height);

应该

contractSuit.frame = CGRectMake(contractSuit.frame.origin.x + contractLabel.frame.origin.x + contractLabel.bounds.size.width + 3, contractSuit.frame.origin.y, contractSuit.frame.size.width, contractSuit.frame.size.height);