android - 如何通过 httpPost() 来隐藏 httpGet()？

Question

这里的 httpPost() java 类，

public String getXmlFromUrl_NewRegistration(String url,
        String username, String firstname, String lastname, String email,
        String password) {
    String json = null;

    try {
        // defaultHttpClient

        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost("http://aleedex.biz/game/users.php?action=new");
        String postParameter = "username=" + username + "&firstname="
                + firstname + "&lastname=" + lastname + "&email=" + email
                + "&password=" + password;

        try {
            httpPost.setEntity(new StringEntity(postParameter));
        } catch (Exception e) {

        }

        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        json = EntityUtils.toString(httpEntity);

    } catch (UnsupportedEncodingException e) {

    } catch (ClientProtocolException e) {

    } catch (IOException e) {

        json = null;
    }

    Log.d("json", json);


    return json;
}

在 httpGet() 中也使用相同的参数，如用户名、名字、姓氏、电子邮件、密码 如何通过 httpGet() 在该链接上使用相同的参数注册用户http://aleedex.biz/game/users.php?action=new

Answer 1

我已经按照该教程解决了我的问题如何将 Android 与 PHP、MySQL 连接起来

Answer 2

在这里，您可以将帖子参数附加到 url，然后进行调用，它可以正常工作

`HttpGet _getrequest=new HttpGet("http://aleedex.biz/game/users.php? action=new&"+postParameter); 

 HttpResponse httpResponse = httpClient.execute(_getrequest);
    HttpEntity httpEntity = httpResponse.getEntity();
    json = EntityUtils.toString(httpEntity);`

试试这个我认为这应该工作。