尝试在不使用 xml 布局的情况下在 android 中创建记忆游戏，基本上我现在要做的是在网格的不同位置创建两张相同的卡片。所以我在这里要问的是如何将这些卡片随机放置在网格上。我首先创建了随机整数数组并且没有重复，但是除非我有一个 if 语句检查是否已经放置了某些东西，否则它将证明是无用的。在键入此内容的过程中，我试图查看是否可以以某种方式放入数组列表并随机排列坐标：S，因此我没有得到任何重复。
public int randomGen(int[]num){
int size =num.length;
for(int j=0;j<size;j++){
num[j]=j;
}
for(int i =0;i<size;i++){
int indexToSwap = random.nextInt(size);
int oldValue = num[i];
num[i] = num[indexToSwap];
num[indexToSwap] = oldValue;
}return num[];
}
cardNumber 将是我分配图片的方式。我正在从表面视图扩展我的屏幕并实现可运行。place card 方法是 Word 类的一部分
public class World {
//show them icons first then take away
static final int WORLD_WIDTH =4;
static final int WORLD_HEIGHT=3;
static final int HIGH_SCORE_INC=5;
static final int SCORE_INCREMENT=1;
boolean grid[][] = new boolean[WORLD_WIDTH][WORLD_HEIGHT];
public CardButton c;
public CardButton cd;
Random random = new Random();
public World(){
placeCards();//place cards will only be called once
}
private void placeCards() {
int world = WORLD_WIDTH * WORLD_HEIGHT;
for(int x=0;x<WORLD_WIDTH;x++)
{
for(int y=0;y< WORLD_HEIGHT;y++){
grid[x][y]= false;
}
}
//this will need to be in for loop
int []rand = new int[WORLD_WIDTH];//this could be one
rand =randomGen(rand);
int cardx = random.nextInt(WORLD_WIDTH);
int cardY = random.nextInt(WORLD_HEIGHT);//this could be one
for(int i = 0;i<world/2;i++){
c= new CardButton(cardX,cardY,i);
grid[cardX][cardy]= true;
//cd=new CardButton(cardX,cardY,i); two cards need to be added with different co ordinates
}
}
}
这是我的 cardButton 类
public class CardButton {
public int cardNum;
private boolean isFacedup;
public int x,y;
public static final int CIRCLE=0;
public static final int SQUARE=1;
public static final int STAR=3;
public static final int HEXAGONNC=4;
public static final int OVAL=5;
public static final int DIAMOND=6;
public static final int REGULAR_DECAGON=7;
public static final int TRIANGLE=8;
public static final int CLOVER = 9;
public static final int DECAGON = 10;
public static final int DECAGONNC = 11;
public CardButton(int x,int y, int cardNumIn){
//passes a string called code base which
cardNum = cardNumIn;
isFacedup = false;
}
public void setFaceUp(){
}
public void setFaceDown(){
}
public boolean isFaceUp(){
return isFacedup;
}
public boolean equals(CardButton card){
return cardNum ==card.cardNum? true:false;
}
}
这将在我的游戏屏幕类中显示方块
private void drawWorld(World world) {
//the integer size will be based on the difficulty perhaps create a constants class
Graphics g = game.getGraphics();
CardButton c = world.c;
CardButton cd = world.cd;
int width = g.getWidth();
int height = g.getHeight();
xpos=width/5;
ypos=height/5;
Pixmap cards = null;
//something to thing about is that although they are two card objects to be created, they will share the same asset
if(c.cardNum==CardButton.CIRCLE)
cards=Assets.circle;
if(c.cardNum==CardButton.CLOVER)
cards=Assets.clover;
if(c.cardNum==CardButton.DECAGON)
cards=Assets.decagon;
if(c.cardNum==CardButton.DECAGONNC)
cards=Assets.decagonnc;
if(c.cardNum==CardButton.SQUARE)
cards=Assets.square;
if(c.cardNum==CardButton.STAR)
cards=Assets.star;
if(c.cardNum==CardButton.HEXAGONNC)
cards=Assets.hexagennc;
if(c.cardNum==CardButton.OVAL)
cards=Assets.oval;
if(c.cardNum==CardButton.OVAL)
cards=Assets.oval;
//this is how many times u wish to see the object
int length;
//this varible will be based on the difficulty
int x = c.x;
int y = c.y;
int sx=cd.x;
int sy=cd.y;
//
for(int i=0;i<2;i++)
{
g.drawPixmap(cards, x, y);
g.drawPixmap(cards, sx, sy);
}
//g.drawRect(10, 10, g.getWidth(), height, Color.WHITE);
/*
* Asset simply holds a constant of pixmaps that later get intialised by loading screen with a string
*/
//g.drawPixmap(Assets.tiles,xpos,ypos);
}