1

我设置了一个 CCMenu，菜单项如下：

    CCLabelTTF *label1 = [CCLabelTTF labelWithString:@"level 1" fontName:@"Marker Felt" fontSize:32];
    CCLabelTTF *label2 = [CCLabelTTF labelWithString:@"level 2" fontName:@"Marker Felt" fontSize:32];
    CCLabelTTF *label3 = [CCLabelTTF labelWithString:@"level 3" fontName:@"Marker Felt" fontSize:32];
    CCLabelTTF *label4 = [CCLabelTTF labelWithString:@"level 4" fontName:@"Marker Felt" fontSize:32];

    CCMenuItem *level1 = [CCMenuItemLabel itemWithLabel:label1 target:self selector:@selector(levelSelect:)];
    level1.tag = 1;
    CCMenuItem *level2 = [CCMenuItemLabel itemWithLabel:label2 target:self selector:@selector(levelSelect:)];
    level2.tag = 2;
    CCMenuItem *level3 = [CCMenuItemLabel itemWithLabel:label3 target:self selector:@selector(levelSelect:)];
    level3.tag = 3;
    CCMenuItem *level4 = [CCMenuItemLabel itemWithLabel:label4 target:self selector:@selector(levelSelect:)];
    level4.tag = 4;
    CCMenu *menu = [CCMenu menuWithItems:level1, level2, level3, level4, nil];
    [menu alignItemsVerticallyWithPadding:20];

有没有办法可以缝制一个 for 循环来遍历每个 CCMenuItem？如果它的标签小于其他东西，我基本上想将启用设置为 no。例如：

for (ALL MENU ITEMS) {
    if (THAT MENU ITEM.tag < 4) {
        THAT MENU ITEM.enabled = NO;
    }
}

提前致谢

4

1 回答 1

4

CCMenuItems被添加为您的 CCMenu 的子项，因此为了遍历它们，您可以这样做。-

for (CCMenuItem *item in [menu children]) {
    if (item.tag < 4) {
        item.enabled = NO;
    }
}
于 2013-04-14T18:00:23.907 回答