1

我有两张桌子。一个包含文章，另一个包含报价。如果两个表中的尺寸匹配，我正在尝试[EAN]从文章表和报价表中进行选择。price

这是我正在玩的例子：

DROP TEMPORARY TABLE IF EXISTS haha;
CREATE TEMPORARY TABLE haha (
    tmp_kto VARCHAR(7) DEFAULT ''
    , tmp_kz VARCHAR(3) DEFAULT ''
    , tmp_preisliste VARCHAR(1) DEFAULT ''
    , tmp_eg VARCHAR(3) DEFAULT ''
    , tmp_length VARCHAR(3) DEFAULT ''
    , tmp_width VARCHAR(3) DEFAULT ''
    , tmp_price DECIMAL(10,2) DEFAULT 0.00
    ) ENGINE=MEMORY;

INSERT INTO haha (
    tmp_kz, tmp_kto, tmp_preisliste, tmp_eg, tmp_length, tmp_width, tmp_price
    ) VALUES (
    "000","4316134","I","520","150","200","14.95"
    );
INSERT INTO haha (
    tmp_kz, tmp_kto, tmp_preisliste, tmp_eg, tmp_length, tmp_width, tmp_price
    ) VALUES (
    "001","112233","L","520","150","200","17.95"
    );

匹配标准应该是[EG]和[size]。因为size我需要从字段中提取相关大小（我认为没有其他方法 - 格式是例如 050x250cm）。

SELECT ean, preis 
    FROM (
    SELECT  a.ean AS ean
           , h.tmp_price AS preis
    FROM articles AS a
    LEFT JOIN haha AS h
        ON h.tmp_eg = a.eg
        AND h.tmp_kz = "000"
        AND h.tmp_kto = "0000000"
        AND h.tmp_preisliste = "I"
        AND h.tmp_length = SUBSTRING(a.size,1,3)
        AND h.tmp_width = SUBSTRING(a.size,4,3)
) AS temp;

哪个不起作用。

问题：
我需要进行哪些更改才能使其正常工作？

编辑
第二张表如下所示：

CREATE TABLE `articles` (
    `id` INT(11) NOT NULL AUTO_INCREMENT,
    `ean` VARCHAR(35) NULL DEFAULT NULL,
    `size` VARCHAR(35) NULL DEFAULT NULL,
    `eg` VARCHAR(35) NULL DEFAULT NULL,
PRIMARY KEY (`id`),
)
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
AUTO_INCREMENT=1;

INSERT INTO articles (
    ean, size, eg
    ) VALUES (
    "1111111111111","150x200cm","520"
    );

INSERT INTO articles (
    ean, size, eg
    ) VALUES (
    "2222222222222","150x220cm","520"
    );

感谢帮助！

4

2 回答 2

1

你为什么不这么简单地使用？

SELECT a.ean, h.tmp_price AS preis 
FROM articles AS a
LEFT JOIN haha AS h
    ON h.tmp_eg = a.eg
WHERE h.tmp_kz = "000"
    AND h.tmp_kto = "0000000"
    AND h.tmp_preisliste = "I"
    AND h.tmp_length = SUBSTRING(a.size,1,3)
    AND h.tmp_width = SUBSTRING(a.size,4,3)
于 2013-04-14T15:22:25.033 回答
0

比想象的容易：

    SELECT a.ean AS ean,
           h.tmp_price AS preis
    FROM articles AS a
    LEFT JOIN haha AS h
    ON h.tmp_eg = a.eg

    WHERE a.iln = "some_id"
    AND h.tmp_kz = "000"
    AND h.tmp_kto = "0000000"
    AND h.tmp_preisliste = "I"
    AND h.tmp_length = SUBSTRING(a.groesse,1,3)
    AND h.tmp_width = SUBSTRING(a.groesse,5,3)
于 2013-04-14T15:32:15.550 回答