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我正在使用此代码段以删除断点 ( <br/>) 并将我的文本包装在段落中：

$('.articleText').contents().filter(function() {
    return this.nodeType == 3;
}).wrap('<p></p>').end().filter('br').remove();

来源：http ://api.jquery.com/contents/

问题是我的文本包含一个未包含在段落中的超链接 () - 它只是被遗漏了......

这是我的文本片段：

Lorem Ipsum is simply dummy text of the printing and typesetting industry. <br/><br/>Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a <a href="#">galley</a> of type and scrambled it to make a type specimen book.

这就是它的转变方式：

<p>Lorem Ipsum is simply dummy text of the printing and typesetting industry.</p>
<p>Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a</p> 
<a href="#">galley</a> 
<p>of type and scrambled it to make a type specimen book.</p>

这应该是这样的：

<p>Lorem Ipsum is simply dummy text of the printing and typesetting industry.</p>
<p>Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a <a href="#">galley</a> of type and scrambled it to make a type specimen book.</p>

这怎么可能...？

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1 回答 1

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该方法.contents()只返回调用者的孩子的内容，而不是所有的后代。因为您的<a>标签嵌套在一个孩子中，所以该方法不会拾取它.contents()。

尝试这个：

$('.articleText').contents().add($(this).find("*").contents())...

注意：我还没有测试过上面的，所以它可能需要一些小的调整。

更新：如果我误解了您并且<a>不应该嵌入标签，那么您的标记中有错误：

尝试改变：

<p>Lorem Ipsum is simply dummy text of the printing and typesetting industry.<p>

至

<p>Lorem Ipsum is simply dummy text of the printing and typesetting industry.</p>


如果您对此有任何疑问，请告诉我。祝你好运！:)

于 2013-04-11T14:03:03.000 回答