ajax - DIV 中的 Ajax 响应

Question

您好，我想稍微修改以下脚本，以便将响应输出到 div 而不是警报，请参见粗体部分。任何帮助表示赞赏！

function processResponse() {
    if (gateway.readyState == 4 && gateway.status == 200) {
        alert("Done loading!\n\nThe response from the PHP script was: "+gateway.responseText);
    }
}

Answer 1

如果 div 有一个 id 尝试这样的事情：

document.getElementById("divId").innerHTML = gateway.responseText;

Answer 2

function processResponse() { 
    if (gateway.readyState == 4 && gateway.status == 200) {
        document.getElementById("yourDiv").innerHTML = "php script was : " + gateway.responseText;
    } 
}

或者如果使用 jquery

function processResponse() { 
    if (gateway.readyState == 4 && gateway.status == 200) {
        $("#youdivid").html("php script was : " + gateway.responseText);
    } 
}