javascript - 使用逻辑 OR 运算符的 if 语句中的多重比较

Question

我想做他以下，但它不起作用：

if(pathname == '/ik/services/' || '/ik/recruitment/'){
   //run function
}

它完全忽略了我的 if 语句并执行所有页面的代码......

Answer 1

你必须做这样的事情：

if(pathname == '/ik/services/' || pathname == '/ik/recruitment/'){
   //run function
}

您|| '/ik/recruitment/'将永远是真实的，因此您的 if 语句中的代码将始终运行。

Answer 2

尝试

if(pathname == '/ik/services/' || pathname == '/ik/recruitment/'){

或者

jQueryinArray

例子

var arr = ['/ik/services/','/ik/recruitment/'];

if($.inArray(pathname , arr) !== -1)

Answer 3

这与jQuery无关，它只是一个普通的JS“错误”。您需要将两个字符串与变量进行比较：

if (pathname == 'foo'  || pathname == 'bar') 

Answer 4

试试这个：

if((pathname == '/ik/services/') || (pathname == '/ik/recruitment/')){
   //run function
}

Answer 5

尝试做

    if(pathname == '/ik/services/' || pathname == '/ik/recruitment/'){
      //run function
    }