0

我在我的应用程序从 yaml 描述文件启动期间动态生成 django 模型。我在 django admin 中注册了它们，但它们在管理界面中显示为禁用。看起来像这样。

我创建了 manage.py 命令来从 yaml 格式的描述文件中动态创建模型。

from django.core.management.base import BaseCommand
from django.core.management import call_command

import yaml

from generation.generate import generate_fields, generate_model


class Command(BaseCommand):
    help = 'Generates or updates django models from specified file'

    def handle(self, *args, **options):
        try:
            f = open(args[0], 'r')
            models = yaml.safe_load(f)
            f.close()
            for name, definition in models.items():
                fields = generate_fields(definition['fields'])
                generate_model(name, definition['title'], fields, "generation", "generation.models")
            call_command('syncdb', interactive=True)
        except IOError:
            self.stderr.write('Cannot open file: {0}'.format(args[0]))
        except yaml.YAMLError as e:
            self.stderr.write('Cannot parse file {0}: {1}'.format(args[0], e))

我从根 urls.py 启动这个命令，如下所示：

from django.conf.urls import patterns, include, url
from django.contrib import admin
from generation import views
from generation.management.commands.updatemodels import Command

admin.autodiscover()

urlpatterns = patterns('',
    url(r'^$', views.main, name='main'),
    # url(r'^modgen/', include('modgen.foo.urls')),

    url(r'^admin/', include(admin.site.urls)),
)

Command().handle('models.yaml')

我以这种方式生成模型并在管理员中注册：

from sys import stderr
from django.contrib import admin
from django.db import models


class Types():
    INT = 'int'
    CHAR = 'char'
    DATE = 'date'


def generate_model(model_name, model_title, fields, app_label, module):
    class Meta:
        pass
    if app_label:
        setattr(Meta, 'app_label', app_label)
    if model_title:
        setattr(Meta, 'verbose_name_plural', model_title)
    attrs = {'__module__': module, 'Meta': Meta}
    if fields is not None:
        attrs = dict(attrs.items() + fields.items())
    model = type(model_name, (models.Model,), attrs)
    admin.site.register(model)


def generate_fields(definition):
    fields = {}
    for field in definition:
        fields[field['id']] = generate_field(field['title'], field['type'])
    return fields


def generate_field(title, field_type):
    if field_type == Types.CHAR:
        return models.CharField(title, max_length=255)
    elif field_type == Types.INT:
        return models.IntegerField(title)
    elif field_type == Types.DATE:
        return models.DateField(title)
    else:
        stderr.write('Unknown field type specified: {0}'.format(field_type))

为什么模型在管理界面中显示为禁用？Django 成功注册了它们。

4

1 回答 1

0

可能，首先您需要编辑（或创建）文件generation/admin.py，然后在 django-admin 部分添加此代码以注册应用程序模型。

from django.contrib import admin
from myproject.generation.models import Rooms, Users

class RoomsAdmin(admin.ModelAdmin):
    pass


class UsersAdmin(admin.ModelAdmin):
    pass


admin.site.register(Rooms, RoomsAdmin)
admin.site.register(Users, UsersAdmin)
于 2013-04-08T02:00:43.597 回答