0

这是我的表结构（fun_users）

id  first_name  last_name   email   passkey place   profession  self_des    profile_img user_type   active  last_login  reg_date    reported_banned

我的友谊表是

id  user_id friend_id   status  date_request    from_ip

这是我用来获取登录用户朋友详细信息的查询

SELECT `fun_friends`.`id` as fid, `fun_users`.`id` as uid, `fun_users`.`first_name`, `fun_users`.`profile_img`, `fun_users`.`profession`, `fun_users`.`place` FROM (`fun_friends`) JOIN `fun_users` ON `fun_users`.`id`=`fun_friends`.`friend_id` WHERE (`fun_friends`.user_id= '".$_SESSION['user_row_id']."' AND  `fun_friends`.`status` =1) OR (`fun_friends`.friend_id= '".$_SESSION['user_row_id']."' AND  `fun_friends`.`status` =1)

结果是

fid uid first_name       profile_img                       profession                             place
11  47  Agnii   thumbs/2013-03-311364721555.jpg       Software engineer                                 somewhere

该查询返回登录用户的详细信息而不是他的朋友详细信息。谁能帮我 ？

4

1 回答 1

1

下面的查询使用子查询获取特定用户的所有朋友。表fun_users与子查询连接两次，因为子查询上有两列依赖于它。

SELECT  a.id AS FID,
        IF(a.user_ID = 'user_row_id_HERE', c.id, b.id) AS UID,
        IF(a.user_ID = 'user_row_id_HERE', c.first_name, b.first_name) AS first_name,
        IF(a.user_ID = 'user_row_id_HERE', c.last_name, b.last_name) AS last_name,
        IF(a.user_ID = 'user_row_id_HERE', c.profile_img, b.profile_img) AS profile_img,
        IF(a.user_ID = 'user_row_id_HERE', c.profession, b.profession) AS profession,
        IF(a.user_ID = 'user_row_id_HERE', c.place, b.place) AS place
FROM
        (
            SELECT  id, user_ID, friend_ID
            FROM    friendship
            WHERE   'user_row_id_HERE' IN (user_ID, friend_ID) AND
                    status = 1
        ) a
        INNER JOIN fun_users b
            ON a.user_ID = b.id
        INNER JOIN fun_users c
            ON a.friend_ID = c.ID

那么问题来了，这条线上会发生什么？

IF(a.user_ID = 'user_row_id_HERE', c.id, b.id) AS UID

基本上，它测试user_ID来自子查询的值是否等于当前用户。如果恰好相等，则fun_users c返回表中的列，反之亦然。

要进一步了解有关联接的更多信息，请访问以下链接：

于 2013-04-07T13:54:00.777 回答