shell - 检查两个进程是否没有在 shell 脚本中运行

Question

如果两个进程未运行，我如何检查“if”条件？

我用过

if [ `pgrep <process name>`] does not work with ot without square brackets
using ps -aux |grep <process name> in if condition does not work, since every time 
grep <process name>
is up and it will always pass

任何人都有任何好的建议，我可以检查是否只需要两个进程“未”运行

谢谢

Answer 1

if [ $(ps aux | grep -E "(processName1|processName2)" | grep -v grep | wc -l) -eq 0 ]
then
    echo "not running"
fi

Answer 2

ps -aux |grep -v <process name> 

-v 是'反向匹配'，IOW，当您要查找的项目不匹配时返回成功