ios - 如何从 plist 中检索字符串？

Question

我在xcode中有一个名为“config.plist”的plist ，我试图检索寄存器url（键：reg）但是当我打印结果时它显示空值？

这是我检索字符串的代码。请参考我的 plist 结构的图像。

NSMutableURLRequest *request =[[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString: [[_config objectForKey:@"URL"] objectForKey:@"reg"]]];

Answer 1

NSString *plist=[[NSBundle mainBundle] pathForResource:@"config" ofType:@"plist"];
NSDictionary *dict=[[NSDictionary alloc] initWithContentsOfFile:plist];
NSString *stringValue=dict[@"URL"][@"reg"];

编辑：了解以下内容非常重要：

在上面dict本身就是objectForKey:@"Root"

我/我们试图找到[@"Root"][@"URL"][@"reg"]不存在的。

因此，对于命名约定（它存储的内容）的可读性，它应该是：

NSString *plist=[[NSBundle mainBundle] pathForResource:@"config" ofType:@"plist"];
NSDictionary *rootDict=[[NSDictionary alloc] initWithContentsOfFile:plist];
NSString *stringValue=dict[@"URL"][@"reg"];

甚至

NSString *plist=[[NSBundle mainBundle] pathForResource:@"config" ofType:@"plist"];
NSString *stringValue=[[NSDictionary alloc] initWithContentsOfFile:plist][@"URL"][@"reg"];

Answer 2

尝试

NSString *path = [[NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0] stringByAppendingPathComponent:@"config.plist"]; 
NSDictionary *dictionary = [[NSDictionary alloc] initWithContentsOfFile:path];
NSString *result = [[[dictionary objectForKey:@"Root"] objectForKey:@"URL"]objectForKey:@"reg"];

编辑资源：

NSString *path = [[NSBundle mainBundle] pathForResource:@"config" ofType:@"plist"];

Answer 3

    NSString *plist=[[NSBundle mainBundle] pathForResource:@"config" ofType:@"plist"];
    NSLog(@"path%@",plist);
    NSDictionary *dict=[[NSDictionary alloc] initWithContentsOfFile:plist];
    NSLog(@"d%@",dict);
    NSString *stringValue=[[dict objectForKey:@"URL"] valueForKey:@"reg"];

这东西对我有用..谢谢你的帮助

Answer 4

试试这个代码

NSString *plistFilePath=[[NSBundle mainBundle] pathForResource:@"config" ofType:@"plist"];
NSDictionary *urlDictionary=[[NSDictionary alloc] initWithContentsOfFile:plistFilePath];
NSString *urlString=[[urlDictionary objectForKey:@"URL"] valueForKey:@"reg"];