iphone - 从 NSMutableArray 中删除某些对象

Question

我有一个NSMutableArray对象，它们属于AdDetail具有一些属性的类（例如 adId、adTitle、adPrice ... 等）。我只想删除那些具有adID = 0. 我怎样才能做到这一点 ？

Answer 1

也许更优雅的东西就足够了？

[array removeObjectsInArray:[array filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"adID == 0"]]];

Answer 2

使用谓词

NSArray *filtered=[array filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(adId == 0)"]];

使用快速枚举：

NSMutableArray *newArray=[NSMutableArray new];
for(AdDetail adDetailObj in array){
    if(![[adDetailObj adId] isEqualToString:@"0"]){ //if these are strings, if NSInteger then directly compare using ==
       newArray[newArray.count]=adDetailObj;
   }
}

现在newArray包含除id=0

Answer 3

NSMutableArray *newArray = [NSMutableArray arrayWithArray:yourArray];

for (int i = 0; i < yourArray.count; i++)
{
     AdDetail *obj = (AdDetail *)[yourArray objectAtIndex:i];
     if (obj.adID == 0)
         [newArray removeObjectAtIndex:i];
}
yourArray = [newArray mutableCopy];

Answer 4

for(i=0; i < myArray.count; i++)
{
  myClass = [myArray objectAtIndex:i];
  if([myClass.adID isEqualtoString:"0"])// if it it int/NSInteger the write myClass.adID==0
  {
            [myArray removeObjectAtIndex:i];
      i--;
  }
}

Answer 5

使用以下代码：

int count = array.count;
for(i=0;i<count;i++){

     ADetail *adetail = [array objectAtIndex:i];
     if(adetail.adID = 0){

         [array removeObjectAtIndex:i];
          i--;

     }
     count = array.count;
}

Answer 6

predicate = @"adID == 0";
newArray = [theArray filterUsingPredicate:aPredicate]