我正在尝试从 sd 卡文件夹中发送图像,但仍然无法做到这一点。我正在使用twitter4j-core-3.0.3
api 并授予权限android.permission.INTERNET
,android.permission.ACCESS_NETWORK_STATE
. 这是我的代码
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
setRequestedOrientation(ActivityInfo.SCREEN_ORIENTATION_PORTRAIT);
mSharedPreferences = getApplicationContext().getSharedPreferences(
"MyPref", 0);
twitterButton = (Button) findViewById(R.id.twitPic);
twitterButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v)
{
new ImageSender().execute();
}
});
if (!isTwitterLoggedInAlready()) {
Uri uri = getIntent().getData();
if (uri != null && uri.toString().startsWith(TWITTER_CALLBACK_URL)) {
// oAuth verifier
String verifier = uri
.getQueryParameter(URL_TWITTER_OAUTH_VERIFIER);
try {
requestToken = twitter
.getOAuthRequestToken(TWITTER_CALLBACK_URL);
// Get the access token
accessToken = twitter.getOAuthAccessToken(
requestToken, verifier);
// Shared Preferences
Editor e = mSharedPreferences.edit();
// After getting access token, access token secret
// store them in application preferences
e.putString(PREF_KEY_OAUTH_TOKEN, accessToken.getToken());
e.putString(PREF_KEY_OAUTH_SECRET,
accessToken.getTokenSecret());
// Store login status - true
e.putBoolean(PREF_KEY_TWITTER_LOGIN, true);
e.commit(); // save changes
Log.e("Twitter OAuth Token", "> " + accessToken.getToken());
} catch (Exception e) {
// Check log for login errors
Log.e("Twitter Login Error", "> " + e.getMessage());
}
}
}
}
private class ImageSender extends AsyncTask<URL, Integer, Long> {
private String url;
protected void onPreExecute() {
pDialog = ProgressDialog.show(MainActivity.this, "", "Sending image...", true);
pDialog.setCancelable(false);
pDialog.show();
}
protected Long doInBackground(URL... urls) {
long result = 0;
Log.d(TAG, "Start sending image...");
try {
String ExternalStorageDirectoryPath = Environment
.getExternalStorageDirectory()
.getAbsolutePath();
String targetPath = ExternalStorageDirectoryPath + "/Friends/"+"image4.jpg";
File targetDirector = new File(targetPath);
ConfigurationBuilder builder = new ConfigurationBuilder();
builder.setOAuthConsumerKey(TWITTER_CONSUMER_KEY);
builder.setOAuthConsumerSecret(TWITTER_CONSUMER_SECRET);
// Access Token
String access_token = mSharedPreferences.getString(PREF_KEY_OAUTH_TOKEN, "");
// Access Token Secret
String access_token_secret = mSharedPreferences.getString(PREF_KEY_OAUTH_SECRET, "");
AccessToken accessToken = new AccessToken(access_token, access_token_secret);
twitter = new TwitterFactory(builder.build()).getInstance(accessToken);
StatusUpdate status = new StatusUpdate("");
status.setMedia(targetDirector);
twitter.updateStatus(status);
result = 1;
Log.d(TAG, "Image uploaded, Twitpic url is " + url);
} catch (TwitterException e) {
Log.e(TAG, "Failed to send image "+e);
e.printStackTrace();
}
return result;
}
protected void onProgressUpdate(Integer... progress) {
}
protected void onPostExecute(Long result) {
pDialog.cancel();
String text = (result == 1) ? "Image sent successfully.\n Twitpic url is: " + url : "Failed to send image";
Toast.makeText(getApplicationContext(), text, Toast.LENGTH_LONG).show();
}
}
private boolean isTwitterLoggedInAlready() {
// return twitter login status from Shared Preferences
return mSharedPreferences.getBoolean(PREF_KEY_TWITTER_LOGIN, false);
}
这是我的日志
04-02 06:38:02.275: E/Tag(1762): Failed to send image 400:The request was invalid. An accompanying error message will explain why. This is the status code will be returned during version 1.0 rate limiting(https://dev.twitter.com/pages/rate-limiting). In API v1.1, a request without authentication is considered invalid and you will get this response.
04-02 06:38:02.275: E/Tag(1762): message - Bad Authentication data
04-02 06:38:02.275: E/Tag(1762): code - 215
04-02 06:38:02.275: E/Tag(1762): Relevant discussions can be found on the Internet at:
04-02 06:38:02.275: E/Tag(1762): http://www.google.co.jp/search?q=b2b52c28 or
04-02 06:38:02.275: E/Tag(1762): http://www.google.co.jp/search?q=11331d43
04-02 06:38:02.275: E/Tag(1762): TwitterException{exceptionCode=[b2b52c28-11331d43], statusCode=400, message=Bad Authentication data, code=215, retryAfter=-1, rateLimitStatus=null, version=3.0.3}
编辑:当我尝试在这部分发推文时
StatusUpdate status = new StatusUpdate("");
status.setMedia(targetDirector);
twitter.updateStatus(status);
然后会产生twitter.updateStatus("If you're reading this on Twitter, it worked!");
同样的错误。
我从几天开始就在上面,但没有得到解决方案。请任何人帮助我解决问题。谢谢